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3 years ago

sixty four students are going on a field trip there is 1 adult for every 8 students how many adults are there ?

Mathematics

2 answers:

Lubov Fominskaja [6]3 years ago

7 0

There will be 8 adults

expeople1 [14]3 years ago

5 0

So what you would do is 64 by 8 and then there is 8 adults for every 8 students

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Multiply the binomials (5x+3) And (2x+4)

Sav [38]

Answer:

(5x+3)(2x+4)=10x^2+26x+12

Step-by-step explanation:

You use FOIL (First, Outer, Inner Last)

First: 5x times 2x= 10x^2

Outer: 5x times 4= 20x

Inner: 3 times 2x= 6x

Last= 3 times 4

Combine 20x and 2x to get 26x

3 0

3 years ago

Find the 50th term sequence 5 , -2 , -9 , -16

Anni [7]

5 - 7 = - 2 ;
- 2 - 7 = - 9 ;
-9 - 7 = -16 ;
"common difference" d is - 7 ;
The n-th term of an arithmetic sequence is of the form an = a1 + (n – 1)d ;
a50 = 5 + 49 × ( - 7 ) = 5 - 343 = - 338;

7 0

3 years ago

Read 2 more answers

Need to figure out x and y

7nadin3 [17]

Answer:

f(X)=7 X=1

X=2. f(X)=14

f(X)=21. X= 3

X=4. f(X)=28

X=5. f(X)=35

just substitute in the equation

3 0

3 years ago

Someone help me!!!please

gregori [183]

9514 1404 393

Answer:

115 square units

Step-by-step explanation:

The area of a parallelogram is the product of base length and height. The height is the perpendicular distance between the bases.

A = bh

A = (23)(5) = 115 . . . . square units

8 0

2 years ago

2 u + 12 < 23 0,1 d + 8 > 0 3 - 4 r > 7 13 < 2 z + 3 6 ≥ 9 - 0, 15 i

BartSMP [9]

Answer:

Part 1) $u< 5.5$

Part 2) $d > -80$

Part 3) $r < -1$

Part 4) $z>5$

Part 5) $i\geq 20$

Step-by-step explanation:

The question is

Solve each inequality for the indicated variable

Part 1) we have

$2u+12$

subtract 12 both sides

$2u< 23-12\\2u$

Divide by 2 both sides

$u< 5.5$

The solution is the interval (-∞,5.5)

In a number line the solution is the shaded area at left of u=5.5 (open circle)

The number 5.5 is not included in the solution

Part 2) we have

$0.1d+8 >0$

subtract 8 both sides

$0.1d > -8$

Divide by 0.1 both sides

$d > -80$

The solution is the interval (-80,∞)

In a number line the solution is the shaded area at right of d=-80 (open circle)

The number -80 is not included in the solution

Part 3) we have

$3-4r> 7$

Subtract 3 both sides

$-4r>7-3\\-4r>4$

Divide by -4 both sides

Remember that, when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

$r < -1$

The solution is the interval (-∞,-1)

In a number line the solution is the shaded area at left of r=-1.1 (open circle)

The number -1.1 is not included in the solution

Part 4) we have

$13< 2z+3$

Subtract 3 both sides

$13-3$

Divide by 2 both sides

$5$

Rewrite

$z>5$

The solution is the interval (5,∞)

In a number line the solution is the shaded area at right of z=5 (open circle)

The number 5 is not included in the solution

Part 5) we have

$6\geq 9-0.15i$

Subtract 9 both sides

$6-9\geq -0.15i\\-3\geq -0.15i$

Divide by -0.15 both sides

Remember that, when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

$20\leq i$

Rewrite

$i\geq 20$

The solution is the interval [20,∞)

In a number line the solution is the shaded area at right of i=20 (closed circle)

The number 20 is included in the solution

6 0

3 years ago