Answer: f(3.5) = 58.20
Step-by-step explanation:
Wow...what degree of exponent are we to assume?
I'll go with 2 as we are only given two exemplars.
f(x) = x² + Ax + B
f(- 2.5) = 9 = (-2.5)² + (-2.5)A + B
f(2.5) = 45 = (2.5)² + (2.5)A + B
we can subtract the first equation from the second
45 - 9 = 2.5² - (-2.5)² + 2.5A - (-2.5A) + B - B
36 = 5A
A = 7.2
45 = (2.5)² + (2.5)7.2 + B
B = 20.75
F(3.5) = 3.5² + 7.2(3.5) + 20.75 = 58.2
Answer:
10,000,000
Step-by-step explanation:
you round up, so that makes it 10,000,000
the solutions to a general quadratic equation is
X=-b±√b²-4ac/2a ,, When ax²+bx+c=0
the discriminant is the expression under the radical b²−4ac
Part A:
discriminant is (-16)² - 4(9)(60) = -1904
there are two complex solutions
Part B:
4x² + 8x − 5 = 0
4x² + 10x -2x - 5=0
2x ( 2x + 5) - 1(2 x + 5) =0
(2x + 5)(2x-1) = 0
/ \
/ \
2x+5 = 0 2x-1 =0
x = -5/2 x = 1/2
It’s going be be 1/50 or 0.02 rate for this problem!
Answer:
10 yrs
Step-by-step explanation:
A=P(1+r/n)^nt, P=initial investment, r=annual interest rate,n=number of compounding periods per year, A=amount after t years
For given problem:
P=37000
r=5.5%=.055
n=1
A=62000
..
62000=37000(1+.055)^t
62/37=1.055^t
tlog(1.055)=log(62/37)
Using log keys on calculator:
t=log(62/37)/log(1.055)≈10 yrs
