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velikii [3]
3 years ago
8

What is 23/9 As a mixed number

Mathematics
1 answer:
True [87]3 years ago
6 0
You would divide 23 by 9, which comes out to 2 , with a remander of 5 .so the 9 would be denominator, the 5 would be the numerator and the 2 would be you mixed number so it would be 2 5 - 9
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the area of a rectangle is 95 square yard. if the perimeter is 48 yards find the length and width of rectangle
Vladimir [108]
Try this option:
according to the condition w+l=48 and w*l=95.
Using these two equation:
\left \{ {{l+w=48} \atop {lw=95}} \right. \ =\ \textgreater \  \   \left[\begin{array}{ccc}l=24- \sqrt{481};w=24+ \sqrt{481}\\ \\l=24+ \sqrt{481};w=24- \sqrt{481}\end{array}
4 0
3 years ago
True or false just answer like that pls
sveta [45]

Answer:

false

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Step-by-step explanation:

brainliest?

3 0
2 years ago
Based on the Information determine which sides of quadrilateral ABCD must be parallel
RUDIKE [14]

The angles must be opposite to be equal to each other so parallelogram ABCD

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C is the correct answer

6 0
3 years ago
There are 7 gallons of black paint available to motorola. If 5/9 gallons is used each run, How many runs can we paint?
nadya68 [22]

There are 7 gallons of black paint available to motorola. If 5/9 gallons is used each run. To find the amount of runs you can paint, you have to divide the total by the amount for each run.

7 \div \frac{5}{9}

When dividing fractions, you have to keep, change, and flip.

Keep\ 7 \\ Change\ \div\ to\ \times \\ Flip \frac{5}{9} = \frac{9}{5}

Your new equation is:

7 \times \frac{9}{5}

Multiply:

7 \times \frac{9}{5} = \frac{63}{5} = 12 \frac{3}{5}

You can paint 12 \frac{3}{5} or 12.6 runs.

4 0
3 years ago
The following data represent the pulse rates? (beats per? minute) of nine students enrolled in a statistics course. Treat the ni
charle [14.2K]

Answer:

(a)77.4bpm

(b)Mean of Sample 1 = 70.3 beats per minute.  

Mean pulse of sample 2 = 70 beats per minute.

(c)

  • The mean pulse rate of sample 1 underestimates the population mean.
  • The mean pulse rate of sample 2 underestimates the population mean.

Step-by-step explanation:

(a)Population mean pulse.

The pulse of the nine students which represent the population are:

  • Perpectual Bempah      64
  • Megan Brooks               77
  • Jeff Honeycutt               89
  • Clarice Jefferson           69
  • Crystal Kurtenbach       89
  • Janette Lantka              65
  • Kevin McCarthy             88
  • Tammy Ohm                  69
  • Kathy Wojdya                 87

\text{Population Mean} =\dfrac{64+77+89+69+89+65+88+69+87}{9} \\=\dfrac{697}{9} \\\\=77.44

The population mean pulse is approximately 77.4 beats per minute.

(b)Sample 1: {Janette,Clarice,Megan}

  • Janette: 65bpm
  • Clarice: 69bpm
  • Megan: 77bpm

Mean of Sample 1

\text{Sample 1 Mean} =\dfrac{65+69+77}{3} \\=\dfrac{211}{3} \\\\=70.3

Sample 2: {Janette,Clarice,Megan}

  • Perpetual: 64bpm
  • Clarice: 69bpm
  • Megan: 77bpm

Mean of Sample 2

\text{Sample 2 Mean} =\dfrac{64+69+77}{3} \\=\dfrac{210}{3} \\\\=70

The mean pulse of sample 1 is approximately 70.3 beats per minute.  

The mean pulse of sample 2 is approximately 70 beats per minute.

(c)

  • The mean pulse rate of sample 1 underestimates the population mean.
  • The mean pulse rate of sample 2 underestimates the population mean.
7 0
3 years ago
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