Answer:
m<QRP=42degrees
m<Q=79degrees
m<P=59degrees
Step-by-step explanation:
A rational expression is a ratio of two polynomials. To add or subtract two rational expressions with the same denominator, we simply add or subtract the numerators and write the result over the common denominator. When the denominators are not the same, we must manipulate them so that they become the same.
The second term of the expansion is
.
Solution:
Given expression:

To find the second term of the expansion.

Using Binomial theorem,

Here, a = a and b = –b

Substitute i = 0, we get

Substitute i = 1, we get

Substitute i = 2, we get

Substitute i = 3, we get

Substitute i = 4, we get

Therefore,



Hence the second term of the expansion is
.
Answer:
5x+8=26.50
Step-by-step explanation:
Because the books are equal in price, we can use x to represent the price of the books and 5 to represent the amount, so it would be written as 5x. Then we add 8 because that's the price of the one DVD. It tells the total is 26.50, so the full equation written would be <u>5x+8=26.50</u>