Answer:
![f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7Bx-4%7D%20%2C%20g%28x%29%3D6x%5E%7B2%7D%5Ctextrm%7B%20or%20%7Df%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D%2Cg%28x%29%3D6x%5E%7B2%7D%20-4)
Step-by-step explanation:
Given:
The function, ![H(x)=\sqrt[3]{6x^{2}-4}](https://tex.z-dn.net/?f=H%28x%29%3D%5Csqrt%5B3%5D%7B6x%5E%7B2%7D-4%7D)
Solution 1:
Let ![f(x)=\sqrt[3]{x}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D)
If ![f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}](https://tex.z-dn.net/?f=f%28g%28x%29%29%3DH%28x%29%3D%5Csqrt%5B3%5D%7B6x%5E%7B2%7D-4%7D)
, then,
![\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bg%28x%29%7D%20%3D%5Csqrt%5B3%5D%7B6x%5E%7B2%7D-4%7D%5C%5Cg%28x%29%3D6x%5E%7B2%7D-4)
Solution 2:
Let ![f(x)=\sqrt[3]{x-4}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7Bx-4%7D)
. Then,
![f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}](https://tex.z-dn.net/?f=f%28g%28x%29%29%3DH%28x%29%3D%5Csqrt%5B3%5D%7B6x%5E%7B2%7D-4%7D%5C%5C%5Csqrt%5B3%5D%7Bg%28x%29-4%7D%3D%5Csqrt%5B3%5D%7B6x%5E%7B2%7D-4%7D%20%5C%5Cg%28x%29-4%3D6x%5E%7B2%7D-4%5C%5Cg%28x%29%3D6x%5E%7B2%7D)
Similarly, there can be many solutions.
Answer:
76.8 inches
Step-by-step explanation:
we have :
1m= 39.37 inches
1.95m =?
we can write:
(1.95m*39.37 inches)/1m=
76.77 inches = 76.8 inches
so finally we have:
1.95m = 76.8 inches
The answer would be 6 exteriors.
Answer:
The answer to your question is $ 8591.04
Step-by-step explanation:
Data
height = 11.4 m
diameter = 12 m
cost = $20/ft³
Process
1.- Calculate the volume of the cone
Formula
Volume = 1/3 πr²h
Substitution
Volume = 1/3 (3.14)(12/2)²(11.4)
Simplification
Volume = 1/3(1288.66)
Volume = 429.55 m³
2.- Calculate the cost
$20 ----------------- 1 m³
x ----------------- 429.55 m³
x = (429.55 x 20)/ 1
x = $ 8591.04
Answer:
A.) The graph of g(x) is the graph of f(x) expanded vertically by a factor of 2, and translated 6 unit(s) up.
Step-by-step explanation:
For vertical expansion by a scale factor of k, the graph of f(x) is transformed to ...
g(x) = k·f(x)
For translation up by k units, f(x) is transformed to ...
g(x) = f(x) +k
___
Comparing the following ...
f(x) = log(x)
g(x) = 2·log(x) +6
We see that a multiplication factor and an addition factor have been applied. That means ...
g(x) is f(x) expanded vertically by a factor of 2, and translated up 6 units.
