Answer:
- A'(4, -4)
- B'(0, -3)
- C'(2, -1)
- D'(3, -2)
Step-by-step explanation:
The coordinate transformation for a 270° clockwise rotation is the same as for a 90° counterclockwise rotation:
(x, y) ⇒ (-y, x)
The rotated points are ...
A(-4, -4) ⇒ A'(4, -4)
B(-3, 0) ⇒ B'(0, -3)
C(-1, -2) ⇒ C'(2, -1)
D(-2, -3) ⇒ D'(3, -2)
_____
<em>Additional comment</em>
To derive and/or remember these transformations, it might be useful to consider where a point came from when it ends up on the x- or y-axis.
A point must have come from the -y axis if rotating it 270° CW makes it end up on the +x-axis. A point must have come from the x-axis if rotating it 270° makes it end up on the +y axis. That is why we write ...
(x, y) ⇒ (-y, x) . . . . . . the new x came from -y; the new y came from x
Answer:
66.5
Step-by-step explanation:
Let θ represent ∠MLK
Arc length (s) = radius (r) · θ (theta must be in radians)
Step-by-step explanation:
Kaleerain5,
In order to get your answer you must remember that if the exponent is negative move to the left and if the exponent is positive you have to move to the right.
- The exponent is negative so move to the left:
Therefore your answer is ".000857."
Hope this helps!
The ratio can be determined as,
Thus, the requried ratio is 7:12.
