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Bumek [7]
2 years ago
13

YU HAVE 1 CASE OF SOAP BARS AND THERE ARE 150 BARS IN A CASE..YU USE 300 BARS OF SOAP PER DAY. HOW MANY CASES DO YOU NEED TO HAV

E ENOUGH FOR 7DAYS?
Mathematics
1 answer:
Fittoniya [83]2 years ago
3 0
If you need 300 bars per day, you need 2 cases per day (2*150 = 300).

Therefore you need 2*7 = 14 cases per week

You can subtract the case you already have leaving you with 13 cases needed
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A veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses
Licemer1 [7]

Answer:

Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

Step-by-step explanation:

We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.

So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;

                    Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = average age of the random sample of horses with colic = 12 yrs

            \mu = average age of all horses seen at the veterinary clinic = 10 yrs

   \sigma = standard deviation of all horses coming to the veterinary clinic = 8 yrs

         n = sample of horses = 60

So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P(\bar X \geq 12)

   P(\bar X \geq 12) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } \geq \frac{12-10}{\frac{8}{\sqrt{60} } } ) = P(Z \geq 1.94) = 1 - P(Z < 1.94)

                                                 = 1 - 0.97381 = 0.0262

Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

4 0
3 years ago
A set of data is given: 3,7,11,11,16. Sue calculated a center of measure and got 9.6. Which center of measure did she calculate.
QveST [7]

Answer: Average or Mean

Step-by-step explanation:

The center of measure calculated was the average or mean. To get the mean of a set of numbers, we have to add all the numbers given and then divide them by the numbers.

In this case, the mean of 3,7,11,11,16 will be:

= (3 + 7 + 11 + 11 + 16) / 5

= 48/5

= 9.6

5 0
3 years ago
if the breadth of rectangle in one third of its length and perimeter is 80 cm find length and breadth of rectangle​
LiRa [457]

Answer:

length = 30 cm

Breadth = 10 cm

Step-by-step explanation:

Length = x cm

Breadth = (1/3)x

Perimeter = 80 cm

2(length + breadth) = 80

2* (x + (1/3)x) = 80

2*(\frac{3}{3}x+\frac{1}{3}x) = 80\\\\2*(\frac{4}{3}x) = 80\\\\\frac{8}{3}x = 80\\\\x = 80*\frac{3}{8}\\\\x = 10*3

x = 30cm

length = 30 cm

breadth = \frac{1}{3}*30=10 cm

6 0
3 years ago
There is a bag filled with 4 blue, 3 red and 5 green marbles.
zhannawk [14.2K]

Answer:

You are selecting marbles with replacement. The marble selections (trials) are independent and the marble selection follows the binomial distribution.

The probability of selecting a red marble the first time is 1313.

(This is because 4 out of 12 marbles are red and412412 reduces to 1313.

The probability of selecting a red marble the second time is 1313.

The marble selections are independent and you can multiply the two probabilities to get the following:

probability of getting 2 reds = (13)2(13)2

=19=19.

So the probability of getting two reds is 1919.

7 0
2 years ago
How do you use words and pictures to show 59 and 95?
nydimaria [60]
Draw a foot ball player with the number 59 on his back , draw him as if he was going to touch down.

And draw a clock with the numbers 95 :00 on it , because there is 95 seconds left on in the quarter.

I really hope that this helped you a lot.  
3 0
3 years ago
Read 2 more answers
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