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raketka [301]
3 years ago
8

The solution set of the equation x^2-4x=0 is?

Mathematics
1 answer:
dezoksy [38]3 years ago
6 0

Answer:


Step-by-step explanation:

x^(2)-4x=0,4 so it would be A hope this helps

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Find the profit or loss if:
Sedaia [141]

Answer:

moncy soup ñomi

Step-by-step explanation:

63=a-=

5 0
3 years ago
How many days will he cut the last section?
e-lub [12.9K]

Solving a linear equation, we will see that after 9 days he cuts the last section.

<h3>how many days will he cut the last section?</h3>

We know that the initial length of the piece of cloth is 20m, and the taylor each day cuts a piece of 2 meters of it.

So, the length as a function on the number of days, is:

L(x) = 20m - 2m*x

Here we just need to solve:

L(x) = 2m

Because the last cut is when the long piece measures 4 meters (in that case he does one cut and has the two final pieces of 2 meters).

Solving that, we get:

20m - 2m*x = 2m

20m - 2m = 2m*x

18m/2m = x = 9

After 9 days he cuts the last section.

If you want to learn more about linear equations:

brainly.com/question/1884491

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8 0
2 years ago
What differentiable functions have an arc length on the interval [a, b] given by the following integrals? Note that the answers
Dafna1 [17]

Answer:

a) \pm 8\frac{x^{5}}{5}+C

b) \pm 4 sin(2x) + C

Step-by-step explanation:

Given integrals are:

a) \int\limits^a_b {\sqrt{{1+64x^{8}} } \, dx ---(1)

b) \int\limits^a_b {\sqrt{1+64cos^{2}(2x)} } \, dx---- (2)

Standard form

                L= \int\limits^a_b {\sqrt{1+(f'(x))^{2}} } \, dx

<h3>Part A</h3>

compare (1) with standard form

[f'(x)]^{2} = 64x^{8}\\f'(x)=\pm 8x^{4}\\f(x)= \pm8\frac{x^{5}}{5}+C

<h3>Part B</h3>

Compare (2) with standard form

[f'(x)]^{2}=64cos^{2}(2x)\\f'(x)= \pm 8cos(2x)\\f(x)=\pm 8\frac{sin(2x)}{2}+C\\f(x)= \pm 4sin(2x)+C

5 0
3 years ago
Which is bigger 2/5 or 3/4
sp2606 [1]
3/4 = 0.75
2/5 = 0.4

0.4 < 0.75

Therefore,

2/5 < 3/4
4 0
3 years ago
Here is a number puzzle that uses math. Some might
amid [387]

Answer:

I think it always work out because they try to manipulate the equation such that you'll get 3

you can actually use other values apart from the ones used

7 0
3 years ago
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