I use the sin rule to find the area
A=(1/2)a*b*sin(∡ab)
1) A=(1/2)*(AB)*(BC)*sin(∡B)
sin(∡B)=[2*A]/[(AB)*(BC)]
we know that
A=5√3
BC=4
AB=5
then
sin(∡B)=[2*5√3]/[(5)*(4)]=10√3/20=√3/2
(∡B)=arc sin (√3/2)= 60°
now i use the the Law of Cosines
c2 = a2 + b2 − 2ab cos(C)
AC²=AB²+BC²-2AB*BC*cos (∡B)
AC²=5²+4²-2*(5)*(4)*cos (60)----------- > 25+16-40*(1/2)=21
AC=√21= 4.58 cms
the answer part 1) is 4.58 cms
2) we know that
a/sinA=b/sin B=c/sinC
and
∡K=α
∡M=β
ME=b
then
b/sin(α)=KE/sin(β)=KM/sin(180-(α+β))
KE=b*sin(β)/sin(α)
A=(1/2)*(ME)*(KE)*sin(180-(α+β))
sin(180-(α+β))=sin(α+β)
A=(1/2)*(b)*(b*sin(β)/sin(α))*sin(α+β)=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)
A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)
KE/sin(β)=KM/sin(180-(α+β))
KM=(KE/sin(β))*sin(180-(α+β))--------- > KM=(KE/sin(β))*sin(α+β)
the answers part 2) areside KE=b*sin(β)/sin(α)side KM=(KE/sin(β))*sin(α+β)Area A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)
Answer:
<h2>(g-f)(10) = - 71</h2>
Step-by-step explanation:
f(x) = x² - 1
g(x) = 2x + 8
To find (g-f)(10) first find ( g - f)(x)
To find ( g - f)(x) subtract f(x) from g(x)
That's
( g - f)(x) = 2x + 8 - ( x² - 1)
Remove the bracket
( g - f)(x) = 2x + 8 - x² + 1
Simplify
( g - f)(x) = - x² + 2x + 9
To find (g-f)(10) substitute the value in the bracket that's 10 into ( g - f)(x)
That is
(g-f)(10) = -(10)² + 2(10) + 9
= - 100 + 20 + 9
= - 100 + 29
= - 71
Hope this helps you
Given that,
An equation : -9c² +2c +3 = 0
To find,
Find the value of x.
Solution,
We have, -9c² +2c +3 = 0
We can solve it using the formula as follows :
Here, a = -9, b = 2 and c =3
Put the values,
So, the solution are -0.47 and 0.69.
Answer:
X-intercepts: (-5,0)
Y-Intercepts: (0,2)
Step-by-step explanation:
