Which of the following sets of values correctly completes the T chart for the equation Y =|3x+1|. -5,1,7
1 answer:
Option C:
5, 1, 7
Solution:
Given equation:
y = |3x + 1|
In the chart, x values are given as –2, 0, 2.
To find the value of y for the corresponding x given.
Substitute x = –2 in the equation of y.
y = |3(–2) + 1|
= |–6 + 1|
= |–5| (Absolute value of a negative number is positive)
y = 5
Substitute x = 0 in the equation of y.
y = |3(0) + 1|
= |0 + 1|
= |1|
y = 1
Substitute x = 2 in the equation of y.
y = |3(2) + 1|
= |6 + 1|
= |7| (Absolute value of a negative number is positive)
y = 7
Option C is the correct answer.
The values of y are 5, 1, 7.
The answer image of the table is attached below.
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Answer: Hello mate!
our equation in this problem is:
Now we have a rule in mathematics when the denominator is zero, the function is undefined (because you can not divide by zero). The two denominators that we have here are:
2x + 3 and x - 7, and now we can see for which values of x these denominators are zero in order to discard the values of x
1) 2x + 3 = 0
x = -3/2 = -1.5
and
2) x - 7 = 0
x= 7
(2x + 3); wich is equal to zero when x = -1.5 and x-7, wich is equal to zero when x = 7.
So just looking at these fractions you could assume that x = 7 and x= -1.5 are not possible solutions.