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hammer [34]
3 years ago
13

If you apply the changes below to the absolute value parent function, f(x) = |x|, what is the equation of the new function?Shift

4 units left.Shift 2 units up
A.g(x)=|x-4|+2

B.g(x)=|x+2|+4

C.g(x)=|x+4|+2

D.g(x)=|x+2|-4

Got the answer its C.
Mathematics
2 answers:
Serjik [45]3 years ago
8 0

Answer: C

<u>Step-by-step explanation:</u>

The general form of the equation is: g(x) = a|x - h| + k  ;

  • "a" represents the vertical stretch <em>(or shrink)</em>
  • "h" represents the x-coordinate of the vertex (left and right)
  • "k" represents the y-coordinate of the vertex (up and down)

4 units left means h = 4

2 units up means k = 2

--> g(x) = |x - 4| + 2

Marina CMI [18]3 years ago
5 0
<h2>Answer:</h2>

Option: C is the correct answer.

                C.   g(x)=|x+4|+2

<h2>Step-by-step explanation:</h2>

The parent function f(x) is given by:

             f(x)=|x|

Now, we know that for any parent function f(x) the transformation of the type:

 f(x) → f(x+k)

is a translation of the function f(x) k units to the right if k<0

and k units to the left if k<0

and the transformation of the type:

           f(x) → f(x)+k

is a translation of a function f(x) k units upward if k>0

and k units downward if k<0

Now here it is given that:

The function f(x) is shifted 4 units left and 2 units up.

Hence, the transformed function g(x) is given by:

g(x)=f(x+4)+2\\\\i.e.\\\\g(x)=|x+4|+2

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omeli [17]

Answer:

g-1(x)=SQRT{(x-4)/2} + 4

Step-by-step explanation:

I assume that the 2 is the exponent so ^ represents exponent

We know your function is g(x)=2(x-3)^2+4

For inverse functions we swap x and y values, note g(x) is like the y value

Isolate for y

y=2(x-3)^2+4

x=2(y-3)^2+4

(x-4)/2 = (y-3)^2

SQRT{(x-4)/2} + 4 = y

Therefore g-1(x)=SQRT{(x-4)/2} + 4

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Help me pleeeaaaasssseeee!!!!!!!
Gnesinka [82]
Sorry cant help you, that's a tough nut to crack! good luck though!
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Helpppp pleaseeeee and could you put an explenation??? pleaseeee
Illusion [34]

Answer:

Step-by-step explanation:

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If you are interested,this is a great way to make a lot of money online! From my experience I would highly suggest you to give i
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Answer:

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Step-by-step explanation:

did anyone ask

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