Answer:
following are the solution to the given points:
Step-by-step explanation:
In point a:
calculating unit vector:
the point Q is at a distance h from P(6,6) Here, h=0.1
the value of Q= (5.92928 ,6.07071 )
In point b:
Calculating the directional derivative of 
at P in the direction of 
In point C:
Computing the directional derivative using the partial derivatives of f.
For this case what you should do is use the following trigonometric relationship:
sin (x) = C.O / h
Where
x: angle
C.O: opposite leg
h: hypotenuse
Substituting the values we have:
sen (60) = long / h
sen (60) = 3 / h
h = 3 / sin (60)
h = 3.46
Answer:
h = 3.46
-18a+17b is the answer because you multiply by -1 to each
Step-by-step explanation:
BE/BC=BD/BA
tHE TWO SIMILAR TRIANGLES ARE BED AND BC. tHE PROPORTION ABOVE REPRESENTS USE OF THE TWO SIMILAR TRIANGLES.
4/(4 + 10) = 5/(5+X) Cross Multiply
4(5+x) = 5(4+10)m
20 +4x=20 +50 subtract 20 from both sides
4x = 50 divide by 4
x =12.5
Answer:
a. 45 π
b. 12 π
c. 16 π
Step-by-step explanation:
a.
If a 3×5 rectangle is revolved about one of its sides of length 5 to create a solid of revolution, we can see a cilinder with:
Radius: 3
Height: 5
Then the volume of the cylinder is:
V=π*r^{2} *h= π*(3)^{2} *(5) = π*(9)*(5)=45 π
b. If a 3-4-5 right triangle is revolved about a leg of length 4 to create a solid of revolution. We can see a cone with:
Radius: 3
Height: 4
Then the volume of the cone is:
V=(1/3)*π*r^{2} *h= (1/3)*π*(3)^{2} *(4) = (1/3)*π*(9)*(4)=12 π
c. We can answer this item using the past (b. item) and solving for the other leg revolution (3):
Then we will have:
Radius: 4
Height: 3
Then the volume of the cone is:
V=(1/3)*π*r^{2} *h= (1/3)*π*(4)^{2} *(3) = (1/3)*π*(16)*(3)=16 π
