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Salsk061 [2.6K]
3 years ago
6

PLEASE HELP I HAVE A TEST AT 2/15!!

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
6 0
Nnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnn sorry
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Reflected across the x-axis and vertically<br> translated up 2 units.
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Incomplete question.

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Serena Williams opened a savings account to deposit all her tennis winnings. She initially deposited $8000. After a year of mont
Radda [10]

Answer:

Step-by-step explanation:

Deposited amount 8000$

One year - 12 months

divide 8000 by 12

666.666666667

so one month

666.666666667

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3 years ago
Which function is non-linear ​
allsm [11]

Answer:

The answer is C

Step-by-step explanation:

The answer is C because if you graph all of these points the only one that isn't linear is C. All the other ones are strait lines.

I hope this helps :))

8 0
3 years ago
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Suppose that A, B, and C are invertible matrices of the same
STALIN [3.7K]

Answer:

Step-by-step explanation:

Given that t A, B, and C are invertible matrices of the same

size.

To pr that (ABC)^{-1} = C^{-1}B^{-1}A^{-1}.

to pr that  ( ABC) (C^{-1}B^{-1}A^{-1})=e

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8 0
3 years ago
: Use The TI Calculator To Answer The Question. Find The Probability That A Z-score Will Be Between 0.7 And 1.4. A) 0.242 O B) 0
ZanzabumX [31]

Answer:

P(0.7

And we can find this probability with the following difference:

P(0.7

We can use the following commands on the ti 84

2nd>VARS>DISTR

And then we look for normalcdf and we input this:

normalcdf(0.7,1.4,0,1)

The other possible code would be:

normalcdf(-1000,1,4,0,1)-normalcdf(-1000,0.7,0,1)

And we got:

P(0.7

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

For this case we want to find this probability:

P(0.7

And we can find this probability with the following difference:

P(0.7

We can use the following commands on the ti 84

2nd>VARS>DISTR

And then we look for normalcdf and we input this:

normalcdf(0.7,1.4,0,1)

The other possible code would be:

normalcdf(-1000,1,4,0,1)-normalcdf(-1000,0.7,0,1)

And we got:

P(0.7

3 0
3 years ago
Read 2 more answers
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