H = 151t - 16t²
The height of the ball when it return to the ground will be 0
0 = 151t - 16t²
The zero product property is that when two numbers are being multiplied and the product is 0, one of them must be equal to 0. Therefore, we can factorize this equation:
16t² - 151t = 0
t(16t - 151t) = 0
By the zero product property:
t = 0 or 16t - 151 = 0
So t = 0 or t = 9.44 seconds
The first solution is before he releases the ball and the second is when the ball comes back to the ground. Thus, the ball's air time is 9.44 seconds.
I got an answer of 58.
Subtract 10 from the side length of 24 to get 14.
And use the side length of 5 to find another side length that also equals 5.
In total all your side lengths would be 10,5,5,24,14. And all of them together to arrive at an answer of 58.
A
i need to put 20 characters in here so imma tell you, just use desmos.com. if you type in the equations, it’ll show you the graph
Answer:
2 x^ (3/2)
Step-by-step explanation:
(x^2+x^2)
----------------
x^1/2
Combine like terms
2x^2
-----------
x^1/2
When dividing exponents with the same base, we subtract
a^b/ a^c = a^ (b-c)
2 * (x^2/ x^1/2) = 2( x^(2-1/2)) = 2 * x^ (3/2)
