Answer:
i think 300$
Step-by-step explanation:
Answer:
Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents.
How long will it take for this population to grow to a hundred rodents? To a thousand rodents?
Step-by-step explanation:
Use the initial condition when dp/dt = 1, p = 10 to get k;

Seperate the differential equation and solve for the constant C.

You have 100 rodents when:

You have 1000 rodents when:

Answer:
Maybe 74
Step-by-step explanation:
42+64=106
180-106=74
x = 1
5(1)= -4y + 4
5= -4y + 4
-4. -4 1 = -4y
y = -¼
x = 2...
10 = -4y + 4 6 = -4y y = -3/2
x = 3..
15 = -4y + 4 11 = -4y y = -11/4