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Aneli [31]
3 years ago
8

a club is holding a raffle. Ten thousand tickets have been sold for $2 each. There will be a 1st prize of $3000, 3 second prizes

of $1000 each, 5 third prizes of $500 each, and 20 consolation prizes of $100 each. Find the expected winnings of a single ticket
Mathematics
1 answer:
seropon [69]3 years ago
4 0

Answer:

1000(1/20000) +

300(2/20000) +

10(20/20000) +

=

1800/20000 = .09

Step-by-step explanation:

Each ticket purchased is expected to win 9 cents

Each ticket purchased cost 75 cents

If you interpret expected winnings per ticket to include the cost then each ticket is expected to lose 66 cents.

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A share of stocks gained 12 points, then lost 114 points, and then gained 218 points. Find the overall change in its value.
VLD [36.1K]

Answer:

The overall change is 116points gained

Step-by-step explanation:

Points gained = 12points

Points lost  = 114points

Points gained  = 218points

Unknown:

Overall change in its value  = ?

Solution:

 The overall change  = Total points gained  - Total points lost

                                    = (218 + 12) - 114

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3 years ago
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3 years ago
A manufacturing company measures the weight of boxes before shipping them to the customers. If the box weights have a population
NikAS [45]

Answer:

<u>The probability that the average weight of the boxes will exceed 94 pounds  is 43.25%</u>

Step-by-step explanation:

1. Let's review the information provided to answer the question correctly:

Mean of the population of box weights = 90 pounds

Standard deviation of the population of box weights = 24 pounds

Sample size = 36 boxes

2. What is the probability that the average weight of the boxes will exceed 94 lb?

For answering this question, we will use the z-scores table.

For using the correct z-score, we should use the correct standard deviation. In this case, we have that:

94 - 90 = 4 pounds above the mean.

4 pounds are 4/24 of the standard deviation,

therefore, simplifying:

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z-score is 0.17 because 4 pounds is 1/6 of the standard deviation (24).

The probability of a z-score is 0.5675, but in this case we're asked by a weight over 94 pounds, not under 94 pounds, thus:

1 - 0.5675 = 0.4325

<u>The probability that the average weight of the boxes will exceed 94 pounds  is 43.25%</u>

8 0
2 years ago
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