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Aneli [31]
3 years ago
8

a club is holding a raffle. Ten thousand tickets have been sold for $2 each. There will be a 1st prize of $3000, 3 second prizes

of $1000 each, 5 third prizes of $500 each, and 20 consolation prizes of $100 each. Find the expected winnings of a single ticket
Mathematics
1 answer:
seropon [69]3 years ago
4 0

Answer:

1000(1/20000) +

300(2/20000) +

10(20/20000) +

=

1800/20000 = .09

Step-by-step explanation:

Each ticket purchased is expected to win 9 cents

Each ticket purchased cost 75 cents

If you interpret expected winnings per ticket to include the cost then each ticket is expected to lose 66 cents.

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Which of the following is a solution for the absolute value inequality |2x – 3| &gt; 6?
Mice21 [21]
This breaks into two inequalities:

2x - 3 > 6

and

-2x + 3 > 6

------------------------

2x - 3 > 6

Add 3 to both sides:

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Read 2 more answers
A wooden log 10 meters long is leaning against a vertical wall with its other end on the ground. The top end of the log is slidi
Andre45 [30]

Answer:

Step-by-step explanation:

This is a related rates problem from calculus using implicit differentiation. The main equation is Pythagorean's Theorem. Basically, what we are looking for is \frac{dx}{dt} when y = 6 and \frac{dy}{dt}=-2.

The equation for Pythagorean's Theorem is

x^2+y^2=c^2 where x and y are the legs and c is the hypotenuse. The length of the hypotenuse is 10, so when we find the derivative of this function with respect to time, and using implicit differentiation, we get:

2x\frac{dx}{dt}+2y\frac{dy}{dt}=0 and divide everything by 2 to simplify:

x\frac{dx}{dt}+y\frac{dy}{dt}=0. Looking at that equation, it looks like we need a value for x, y, \frac{dx}{dt} and \frac{dy}{dt}.

Since we are looking for \frac{dx}{dt}, that can be our only unknown and everything else has to have a value. So what do we know?

If we construct a right triangle with 10 as the hypotenuse and use 6 for y, we can solve for x (which is the only unknown we have, actually). Using Pythagorean's Theorem to solve for x:

x^2+6^2=10^2 and

x^2+36=100 and

x^2=64 so

x = 8.

NOW we can fill in the derivative and solve for \frac{dx}{dt}.

Remember the derivative is

x\frac{dx}{dt}+y\frac{dy}{dt}=0 so

8\frac{dx}{dt}+6(-2)=0 and

8\frac{dx}{dt}-12=0 and

8\frac{dx}{dt}=12 so

\frac{dx}{dt}=\frac{12}{8}=\frac{6}{4}=\frac{3}{2}=1.5 m/sec

7 0
3 years ago
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