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Aneli [31]
3 years ago
8

a club is holding a raffle. Ten thousand tickets have been sold for $2 each. There will be a 1st prize of $3000, 3 second prizes

of $1000 each, 5 third prizes of $500 each, and 20 consolation prizes of $100 each. Find the expected winnings of a single ticket
Mathematics
1 answer:
seropon [69]3 years ago
4 0

Answer:

1000(1/20000) +

300(2/20000) +

10(20/20000) +

=

1800/20000 = .09

Step-by-step explanation:

Each ticket purchased is expected to win 9 cents

Each ticket purchased cost 75 cents

If you interpret expected winnings per ticket to include the cost then each ticket is expected to lose 66 cents.

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Step-by-step explanation:

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Step-by-step explanation:

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Is 3 a factor of 73? ( Yes ) or ( No )
Mkey [24]

Answer:

The correct answer is no.

Step-by-step explanation:

If a number is a factor of another number, that means that it can be equally divided into it <em>evenly</em>.

I know that 3 x 20 = 60, and 73 - 60 = 13.

Since 3 is <em>not</em> a factor of 13, it is also <em>not</em> a factor of 73.

Hope this helps! :D

6 0
3 years ago
I need to see how to work this problem 6-(-7)=
alisha [4.7K]
Hi there!

Here is what the rules says

+ * + = +  (Plus times plus = plus)
+*- = - (Plus times minus = minus)
- * - = + (Minus times minus = Plus
- * + = -  (minus times plus = minus)

You need to know the rules by heart because you will use it a lot.

So let see how it works with the problem

6 -(-7)
What does the rules say? It says
- * - = plus  
So, we gonna use PLUS for the sign
6-(-7) = 6 + 7 = 13

13 is the correct answer.

I hope I helped. Please let me know if you have more questions.
3 0
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Transitive property is your answer

if ∠A ≅ ∠C, and ∠C ≅ ∠B then, ∠A ≅ ∠B

hope this helps

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