All categories

3 years ago

Domain and range for y=x^2+5x-6

Mathematics

1 answer:

enyata [817]3 years ago

8 0

Step-by-step explanation:

domain is all real numbers since its quadratic: (-infinity, infinity)

Range is from -6 to positive infinity or [-6, infinity)

You might be interested in

you roll a fair 6-sided die. What is P ( roll a 2 )? if necessary round your answer to 2 decimal places.

xxTIMURxx [149]

Answer:

16.66%

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Give the exact form and decimal form of the equation

Svet_ta [14]

Answer:

Exact form: $\sin{(6x)} = \frac{8}{9}$

Decimal form: $\sin{(6x)} = 0.8889$

The solution for x is: The solution for x is of 10.455º

Step-by-step explanation:

We are given the following equation:

$8 = 9\sin{(6x)}$

Placing into the desired format, the exact format is:

$\sin{(6x)} = \frac{8}{9}$

In the decimal part, we divide 8 by 9. So

$\sin{(6x)} = 0.8889$

Solving for x:

We apply the inverse sine. So

$\sin^{-1}{\sin{(6x)}} = \sin^{-1}{0.8889}$

$6x = 62.73$

$x = \frac{62.73}{6}$

$x = 10.455$

The solution for x is of 10.455º

5 0

3 years ago

The sugar content of the syrup in canned peaches is normally distributed. A random sample of n = 10 cans yields a sample standar

Serggg [28]

Answer:

The 95% confidence interval is given by:

3.30<σ<8.76

Step-by-step explanation:

1) Data given and notation

s=4.798 represent the sample standard deviation

$\bar x$ represent the sample mean

n=10 the sample size

Confidence=95% or 0.95

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=10-1=9$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a tabel to find the critical values.

The excel commands would be: "=CHISQ.INV(0.025,9)" "=CHISQ.INV(0.975,9)". so for this case the critical values are:

$\chi^2_{\alpha/2}=19.022$

$\chi^2_{1- \alpha/2}=2.700$

And replacing into the formula for the interval we got:

$\frac{(9)(4.798)^2}{19.022} \leq \sigma \frac{(9)(4.798)^2}{2.700}$

$10.892 \leq \sigma^2 \leq 76.736$

Now we just take square root on both sides of the interval and we got:

$3.30 \leq \sigma \leq 8.76$

So the best option would be:

3.30<σ<8.76

7 0

3 years ago

Which relation is a function? Graph with 5 points plotted at (negative 3, 2), (negative 2, 2), (negative 1, 2), (negative 2, neg

Olenka [21]

Answer:

use the verticle line test. if a verticle line touches two points on the graph then it is not a function, if the verticle line only touches one point then it is a function.

for your question the answer is the 3rd option - Graph with 5 points plotted at (negative 3, 2), (negative 2, negative 1), (0, 3), (1, 0), and (2, negative 3)

3 0

3 years ago

What is √18x^6 written in simplest for? assume all variables are positive.

Nadya [2.5K]

Your answer should be C. 3x^3√2

3 0

3 years ago