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MAVERICK [17]
2 years ago
7

Renting a car costs $35.50 per day, plus 40¢ per mile. If a customer paid $131 for a 2-day rental, how many miles was the car dr

iven?
Mathematics
2 answers:
qwelly [4]2 years ago
6 0

Subtract the fee from the total:

131- 35.50 = 95.50

Now divide that by the price per mile:

95.50/ 0.40 = 238.75

They drove 238.74 miles

vivado [14]2 years ago
5 0

Answer:

150 miles. (Brainliest Please)

Step-by-step explanation:

We can find the answer by multiplying the rate per day by 2 because the customer rented it for 2 days and then finding out how many miles fit into the remaining amount of money.

$35.50 + $35.50 = $71

$131 - $71 = $60

60 ÷ 0.40 = 150

So the customer drove 150 miles using the rented vehicle.

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What is the expression 6π -3(y+2)
romanna [79]
Y=4


Don’t judge if I’m wrong

Simplifies it would be 18.34-6y-6
7 0
3 years ago
Find the value of k for which the line y = kx + 6 is a tangent to the curve x^2 + y^2 – 10x + 8y = 84
guajiro [1.7K]

Answer:

k = 1/2

Step-by-step explanation:

input y = kx +6 into the equation of the curve x² + y² – 10x + 8y = 84

x² + (kx + 6)² - 10x + 8(kx + 6) = 84

expand:

x² + k²x² + 12kx + 36 - 10x + 8kx + 48 = 84

simplify by collecting like terms:

x² + k²x² + 20kx - 10x + 84 = 84

subtract 84 on both sides to bring it to the left:

x² + k²x² + 20kx - 10x + 84 - 84 = 0

x² + k²x² + 20kx - 10x = 0

factorise out x:

x²(1 + k²) + x(20k - 10) = 0

using the discriminant b² - 4ac where b is 20k - 10, a is 1 + k² and c is 0, substitute them in the formula b² - 4ac:

b² - 4ac

(20k - 10)² - 4(1 + k²)(0) = 0

the part highlighted in bold is gone because it's all multiplied by 0, so we are left with (20k - 10)² = 0

(20k - 10)² is the same as

(20k - 10)(20k - 10)

equate both to 0

20k - 10 = 0 and 20k - 10 = 0

add 10 on both sides

20k = 10 and 20k = 10

divide 20 on both sides

k = 10/20 and k = 10/20 which are both the same

10/20 is simplified to 1/2

k = 1/2

5 0
2 years ago
Somebody please help me with this !!!
Damm [24]

Step-by-step explanation:

Case 1 :

3x + 2y = 6 \\ 4x + y = 2 \\ 3x = 6 - 2y \\ x =  \frac{6 - 2y}{3}  = \\ x = 2 -  \frac{2y}{3}  \\ 4(2 -  \frac{2y}{3} ) + y = 2 \\ 8 -  \frac{8y}{3}  + y = 2 \\  - 1.67y =  - 6 \\

y = 3.59 \\ x = 2 -  \frac{2y}{3}  \\x =  2 -  \frac{2 \times 3.59}{3}  \\  \\ x =  - 0.39

Case 2 :

3x + 2y = 6 \\ 4x  -  y = 2 \\ x = 2 -  \frac{2y}{3}  \\ 4(2 -  \frac{2y}{3} ) - y = 2 \\ 8 -  \frac{8y}{3}  - y = 2 \\   - 3.67y=  - 6 \\ y = 1.63

x = 2 -  \frac{2y}{3}  \\ x = 2 -  \frac{2 \times 1.63}{3}  \\ x = 2 - 1.087 \\ x = 0.913

7 0
3 years ago
Determine the slope-intercept form of the equation of the line parallel to y = x + 11 that passes through the point (–6, 2).
KATRIN_1 [288]

Answer:

y=4x+6

Step-by-step explanation:

4 0
3 years ago
Ivan says if the line passes through a negative number on the x-axis its load must be negative can you prove him wrong or right.
spin [16.1K]

Answer:

Step-by-step explanation:

8 0
2 years ago
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