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MAVERICK [17]
3 years ago
7

Renting a car costs $35.50 per day, plus 40¢ per mile. If a customer paid $131 for a 2-day rental, how many miles was the car dr

iven?
Mathematics
2 answers:
qwelly [4]3 years ago
6 0

Subtract the fee from the total:

131- 35.50 = 95.50

Now divide that by the price per mile:

95.50/ 0.40 = 238.75

They drove 238.74 miles

vivado [14]3 years ago
5 0

Answer:

150 miles. (Brainliest Please)

Step-by-step explanation:

We can find the answer by multiplying the rate per day by 2 because the customer rented it for 2 days and then finding out how many miles fit into the remaining amount of money.

$35.50 + $35.50 = $71

$131 - $71 = $60

60 ÷ 0.40 = 150

So the customer drove 150 miles using the rented vehicle.

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I entered the equation into a graphing calculator. clicked table and then scrolled down to the profit of $3,563. 55 skateboards
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From the airport hanger H, an areoplane A is 18km away on the bearing of 115° while another aeroplane B is 29km away on a bearin
maks197457 [2]

The difference in distance between Aero plane A and B is; 34.67 km

<h3>How to calculate bearing?</h3>

To get the bearing;

∠H = (115 - 90) + (270 - 203)

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Then, we will use cosine rule to get the distance between both Planes A and B.

d_ab = √(18² + 29² - 2(18 * 29) * cos 92)

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2 years ago
Fraction less than 1/2
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8 0
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NASA is conducting an experiment to find out the fraction of people who black out at G forces greater than 6. In an earlier stud
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Answer:

The large sample n = 190.44≅190

The  large  sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 85% confidence level with an error of at most 0.04 is n = 190.44

<u>Step-by-step explanation</u>:

Given  population proportion was estimated to be 0.3

p = 0.3

Given maximum of error E = 0.04

we know that maximum error

M.E = \frac{Z_{\alpha } \sqrt{p(1-p)} }{\sqrt{n} }

The 85% confidence level z_{\alpha } = 1.44

\sqrt{n} = \frac{Z_{\alpha } \sqrt{p(1-p)} }{m.E}

\sqrt{n} = \frac{1.44X\sqrt{0.3(1-0.3} }{0.04}

now calculation , we get

√n=13.80

now squaring on both sides n = 190.44

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<u>Conclusion</u>:-

Hence The  large  sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 85% confidence level with an error of at most 0.04 is n = 190.44

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3 years ago
3 lines are shown. A line with points T, R, W intersects a line with points V, R, S at point R. A line extends from point R to p
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Answer:

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