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dedylja [7]
3 years ago
13

Which statement is true about an object moving in a circular motion due to centripetal force, F, when the mass is doubled?

Physics
1 answer:
marshall27 [118]3 years ago
4 0

Ans) A) Centripetal force will be doubled.

See centripetal force F = mv^2/r

That means centripetal force is directly proportional to the mass of the particle

So, if we double the mass, centripetal force will be increased by twofolds.

So, option A) is correct.

Now, looking at the other options,

B) says centripetal force is unaltered which is incorrect as centripetal force has been altered and increased twofold.

Option C) and D) reduces centripetal force which are also not possible here.

So, only Option A) is correct

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Which type of force will an object move towards?
Makovka662 [10]

Answer:

i think it's weakest

EDIT: It's net. I answered weakest but it was wrong and the correct answer was net. oops

Explanation:

if a strong force is acting on something it will push it away, meaning the object would go towards the weaker force

4 0
2 years ago
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In your own words, explain why sinkholes are very common in Florida. List one use of sinkholes in Florida.
melamori03 [73]
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dont use my words put this in your own hope it helps you understand it better</span>
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3 years ago
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Does anyone know this???
Gelneren [198K]

Answer:

C

Explanation:

8 0
3 years ago
. A spring has a length of 0.200 m when a 0.300-kg mass hangs from it, and a length of 0.750 m when a 1.95-kg mass hangs from it
kap26 [50]

Answer:

29.4 N/m

0.1  

Explanation:

a) From the restoring Force we know that :  

F_r = —k*x  

the gravitational force :  

F_g=mg  

Where:

F_r is the restoring force .

F_g is the gravitational force

g is the acceleration of gravity

k is the constant force  

xi , x2 are the displacement made by the two masses.

Givens:

<em>m1 = 1.29 kg</em>

<em>m2 = 0.3 kg  </em>

<em>x1   = -0.75 m  </em>

<em>x2 = -0.2 m </em>

<em>g   = 9.8 m/s^2  </em>

Plugging known information to get :

F_r =F_g

-k*x1 + k*x2=m1*g-m2*g

k=29.4 N/m

b) To get the unloaded length 1:  

l=x1-(F_1/k)

Givens:

m1 = 1.95kg , x1 = —0.75m  

Plugging known infromation to get :

l= x1 — (F_1/k)  

= 0.1  

 

3 0
3 years ago
4. Two particles, A and B, are in uniform circular motion about a common center. The acceleration of particle A is 7.3 times tha
HACTEHA [7]

Answer:

Explanation:

Acceleration of particle A is 7.3 times the acceleration of particle B.

Let the acceleration of particle B is a, then the acceleration of particle A is

7.3 a.

Let the period of particle A is T and the period of particle B is 2.5 T.

Let the radius of particle A is RA and the radius of particle B is RB.

Use the formula for the centripetal force

a=r\omega ^{2}=r\times \frac{4\pi^{2}}{T^{2}}

So, r = a\frac{T^{2}}{4\pi^{2}}

The ratio of radius of A to the radius of B is given by

\frac{R_{A}}{R_{B}}=\frac{a_{A}\times T_{A}^{2}}{a_{B}\times T_{B}^{2}}

\frac{R_{A}}{R_{B}}=\frac{7.3 a\times T^{2}}{a\times 6.25T^{2}}

RA : RB = 1.17

3 0
2 years ago
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