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vampirchik [111]
4 years ago
12

Sa=2πr²+2πrh solve for h

Mathematics
1 answer:
oksian1 [2.3K]4 years ago
8 0
SA = 2πr²+ 2πrh 
<span>SA- 2πr² = 2πrh </span>
<span>therefore, h= (SA- 2πr²) / 2πr</span>
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4 0
3 years ago
Part A: Determine if the expression is one of our special products. If so, identify it by its general form:
kondaur [170]

Answer:

1.

Part A: Yes, it is (a - b)².

Part B: a² - 2ab + b² => (x - 6)² = x² - 12x + 36.

Part C: x² - 12x + 36.

2.

Part A: Not a special product.

Part B: Binomial distribution => (x + 8)(x + 1) = x² + 9x + 8.

Part C: x² + 9x + 8.

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Part A: Yes, it is (a + b)²

Part B: a² + 2ab + b² => (3x + 2)² = 9x² + 12x + 4.

Part C: 9x² + 12x + 4.

4.

Part A: Yes, it is (a + b)(a - b), a difference of squares.

Part B: a² - b² => 4x² - 49

Part C: 4x² - 49

5.

Part A: Not a special product.

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Part C: 2x² - 15x + 25

6 0
3 years ago
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Dmitrij [34]

Answer:Here, Just substitute their values, 4x + 3y= 4(3) + 3(6)= 12 + 18= 30In short, Your Answer ...

Step-by-step explanation: i am good at math lol

5 0
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Is it true or false! I need help fast thanks!
ladessa [460]

The answer is True.

On differentiating using product rule,

\mathsf {\frac{d}{dx}[xe^{x}] = x(e^{x})+e^{x}(1)}

\mathsf {\frac{d}{dx}[xe^{x}] = e^{x}(x + 1)}

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8 0
2 years ago
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Semenov [28]

Answer:

4

Step-by-step explanation:

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  • 18-14
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5 0
3 years ago
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