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kobusy [5.1K]
3 years ago
11

Tony made $172.50 tutoring last weekend. He tutored for 7 1/2 hours. How much does Tony charge per hour to tutor?​

Mathematics
1 answer:
kykrilka [37]3 years ago
7 0

Answer:

$23 an hour.

Step-by-step explanation:

divide 172.50 by 7.5

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Charra [1.4K]

Answer:

5x 1/4

Step-by-step explanation:

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What is the area of 2 yards
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The area of two yards is 18ft
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What is the area of the trapezoid shown below?
andrew-mc [135]
Ok so the triangle part is 10 but I don’t know what the rectangle part is but the formula for a rectangle is A=base x high
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A cement walk 3 ft wide is placed around the outside of a rectangular garden plot that is 20ft by 30ft. Find the cost of the wal
Inessa05 [86]

Let us calculate the area of the walk.

Since the width of the walk is 3 feet, and the walk will be placed all the 4 sides,

Length of the plot including walk = 20 + (2 × 3) = 20 + 6 = 26 feet.

Breadth of the plot including walk = 30 + (2 × 3) = 36 feet.

Area of the plot including walk = 26 × 36 square feet.

Area of the plot = 20 × 30 square feet.

Area of the walk = (26 × 36) - (20 × 30)

= 936 - 600

= 336 square feet.

= \frac{336}{3(3)} square yards

= 37.3 square yards

Cost of the walk per square yard = $12.25.

Therefore, total cost of the walk = 12.25 × 37.3 = $456.92.

7 0
3 years ago
A store has been selling 300 Blu-ray disc players a week at $600 each. A market survey indicates that for each $40 rebate offere
timurjin [86]

Answer:

75 $

Step-by-step explanation:

According to problem statement p(300) = 600

And we know that with a rebate of 40 $, numbers of units sold will increase by 80 then if x is number of units sold, the increase in units is

(  x  - 300 )  , and the price decrease

(1/80)*40  =  0,5

Then the demand function is:

D(x)  =  600  - 0,5* ( x - 300 )  (1)

And revenue function is:

R(x) =  x * (D(x)   ⇒   R(x) =  x* [  600  - 0,5* ( x - 300 )]

R(x) = 600*x  - 0,5*x * ( x - 300 )

R(x) = 600*x - 0,5*x² - 150*x

R(x) = 450*x  - (1/2)*x²

Now taking derivatives on both sides of the equation we get

R´(x) =  450  - x

R´(x) =  0       ⇒   450  - x = 0

x = 450 units

We can observe that for   0 < x  < 450  R(x) > 0 then R(x) has a maximum for x = 450

Plugging this value in demand equation, we get the rebate for maximize revenue

D(450)  =  600  - 0,5* ( x - 300 )

D(450)  =  600 - 225 + 150

D(450)  =

D(450)  =  600 - 0,5*( 150)

D(450)  =  600 - 75

D(450)  = 525

And the rebate must be

600 - 525  = 75 $

5 0
3 years ago
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