Answer:
45,9
Step-by-step explanation:
Answer:
Step-by-step explanation:
The correct question is
Zena needs a salesperson. Salesperson A is offering his services for an initial $50 in addition to $5 per hour. salesperson B is offering her services for an initial $40 in addition to $7 per hour. When will the two coaches charge the same amount of money?
Let
x ----> the number of hours
y ----> the total charge
we know that
Salesperson A
------> equation A
Salesperson B
------> equation B
To find out when the two coaches charge the same amount of money, equate equation A and equation B and solve for x
7x+40=5x+50
7x-5x=50-40
2x=10
<h2>x=5 hours i think just im not sure but i tried</h2>
Answer:
D. x^2 +14x + 40
Step-by-step explanation:
(x+4)(x+10)
x^2+10x+4x+40
x^2+14x+40
4x-1=x+26
3x-1=26
3x=27
x=9
PLZ Make Me Brainliest
Okay so lets call Leah "L" and her cousin "C". We know that L+C=36 ... we also know that Leah is twice her cousins age. Therefore, L=2 times C, or L=2C. This is because Leah's age is equivalent to twice as much as her cousin's.
Now that you know that L=2C, you can plug this back into the equation. This should make it so that's there's only one variable now!
L+C=36
(2C)+C=36 ... here we subbed in L=2C
3C=36 ... we add up the C's
C=12 ... we isolate for C by dividing both sides by 3
So her cousin's age is 12 years old. Leah's age is twice that. Thus, she's 24. If you add the two up: 12+24, you indeed get 36. Hope that helps :))
