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OLEGan [10]
3 years ago
5

If AB = 8, BC = 16, and CA = 13, list the angles of ABC in order from smallest to largest.

Mathematics
1 answer:
iragen [17]3 years ago
3 0
C, B, A
Explanation:In any triangle, there is a direct relation between the measure of the angle and the length of the opposite side.This means that:- The longest side will be the one opposite to the largest angle- The shortest side will be the one opposite to the smallest angle
In the given triangle:- The longest side is BC, this means that the largest angle is angle A- The shortest side is AB, this means that the smallest angle is C- CA has an intermediate length (AB < CA < BC), this means that measure angle B will be greater than C and less than A
Based on the above, the order from the smallest angle to the largest angle will be as follows:C < B < A
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The formula for the area of a rhombus is A = a equals StartFraction one-half EndFraction d 1 d 2.D1d2, where d1 and d2 are the l
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Answer:

d1=2A/d2

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Step-by-step explanation:

The options of this question are:

1. d₁=2Ad₂

2. d₁= 2A/d₂

3. d₂= d₁/2A

4. d₁= 2A/d₂

5. d₂= 2Ad₁

Given:

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Similarly, from the previous equation

2A=d1*d2

Divide both sides by d1

2A/d1=d1*d2/d1

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Therefore,

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3 years ago
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The result is 42.
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