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Aleks04 [339]
2 years ago
14

60 points! No links or cheaters! I need a serious answer! Someone please help me I need to bump up my grade!

Mathematics
1 answer:
ser-zykov [4K]2 years ago
5 0

Answer:

this is easy, just move them to each other so that they can fit together and make sure they are both either a positive slope or a negative slope. then do the slope formula

Step-by-step explanation:

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I dont get it plzzz help me
cricket20 [7]

Given Equation: \frac{1}{3}h-4(\frac{2}{3}h-3)=\frac{2}{3}h-6

Let us remove parenthesis first.

In order to remove parenthesis, we need to distribute -4 over parenthesis (2/3 h -3).

Distributing -4 over (2/3 h -3), we get,

-4*2/3 h - 4*-3 = -8/3 h + 12.

Substituting this value in original equation, we get

\frac{1}{3}h-\frac{8}{3}h+12 =\frac{2}{3}h-6

Now, in order to make the equation easy to solve, we always remove fractions. In order to remove fraction, we need to find the lowest common denominator of all terms(lcd).

The fraction terms has 3 in denominators, so we could multiply each and every term by 3 to remove 3's from denominators.

Multiplying each equation by 3, we get,

3*\frac{1}{3}h-3*\frac{8}{3}h+3*12 =3*\frac{2}{3}h-3*6

On simplfying this step, we get

1h -8h+36=2h-18

Combining like terms on left side, we get

-7h +36 = 2h -18.

Subtracting 36 from both sides, we get

-7h +36 -36= 2h -18-36.

-7h=2h-54

Subtracting 2h from both sides, we get

-7h-2h=2h-54-2h

-9h = -54

Dividing both sides by -9.

-9h/-9 = -54/-9

h = 6.

Therefore, final answer is h=6.


5 0
4 years ago
Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)
Mnenie [13.5K]
One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
(x-h)^2+(y-k)^2=r^2
the center is (h,k) and the radius is r

and the distance formula is
distance between (x_1,y_1) and (x_2,y_2) is
D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}


r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle


so
(x+2)^2+(y-3)^2=18
(x-(-2))^2+(y-3)^2=(\sqrt{18})^2
(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2

the radius is 3\sqrt{2}
center is (-2,3)

find distance between (8,4) and (-2,3)

D=\sqrt{(8-(-2))^2+(4-3)^2}
D=\sqrt{(8+2)^2+(1)^2}
D=\sqrt{10^2+1}
D=\sqrt{100+1}
D=\sqrt{101}




r=3\sqrt{2}≈4.2
D=\sqrt{101}≈10.04

do r<D

(8,4) is outside the circle

6 0
4 years ago
PLEASE HELP WILL GIVE BRAINLIEST
Svetach [21]

Answer:

Check explanation

Step-by-step explanation:

I'll give you my way of solving it and you can figure it out from there.

<CEA = <DEB due to vertical angles

AE = ED due to midpoint theorem

<CAD = <ADB due to alternating angles theorem

thus two triangles congruent due to ASA

5 0
3 years ago
What is the y-intercept of y=1+6x? Choose 1 answer: (Choice A) A (0,1) (Choice B) B (1,0) (Choice C) C (6,0) (Choice D) D (0,6)
Lerok [7]
The y-intercept of a line equation is when x=0.

Therefore y=1+(6•0)

y=1

Therefore coordinates are (0,1) which is choice A
6 0
3 years ago
Find the value of x in the triangle shown below.
Fittoniya [83]

Answer:

20

Step-by-step explanation:

This triangle can be solved using the Pythagorean theorem. 16^2+12^2=x^2. 16^2+12^2=400. If we set 400 equal to x^2, x=20.

8 0
4 years ago
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