Complete the square for the equation.<br> 14. x2 + 4x + 5 = 0

cheese cubes are sold in packs of 60. crackers are sold in packs of 12. to make 60 snacks of 2 cheese cubes and 1 cracker, what

Reil [10]

Well, you need 2 cheese packs to get 120. and 12x5 is 60 so 5 crackers. 2 cheese 5 crackers

5 0

3 years ago

Read 2 more answers

How do you find the value of a number

VikaD [51]

We calculate it by multiplying the place value and face value of the digit. For instance: If we consider a number 45. Here the digit 4 is in the tens column.

7 0

3 years ago

Pls help I will mark brainlist!!!

STALIN [3.7K]

Answer It’s b
Explanation

6 0

3 years ago

One-third times the difference of a number and 5 is

AfilCa [17]

Answer:

the value of x is 3

Step-by-step explanation:

Hope this helps!!!! :)

5 0

3 years ago

A cellphone provider has the business objective of wanting to estimate the proportion of subscribers who would upgrade to a new

stiv31 [10]

Answer:

$z=\frac{0.27 -0.2}{\sqrt{\frac{0.2(1-0.2)}{500}}}=3.913$

$p_v =P(z>3.913)=0.000046$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of subscribers that would upgrade to a new cellphone at a reduced cost is significantly higher than 0.2 or 20%

Step-by-step explanation:

Data given and notation

n=500 represent the random sample taken

X=135 represent the subscribers that would upgrade to a new cellphone at a reduced cost

$\hat p=\frac{135}{500}=0.27$ estimated proportion of subscribers that would upgrade to a new cellphone at a reduced cost

$p_o=0.2$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that true proportion is higher than 0.2 or not.:

Null hypothesis: $p \leq 0.2$

Alternative hypothesis: $p > 0.2$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info required we can replace in formula (1) like this:

$z=\frac{0.27 -0.2}{\sqrt{\frac{0.2(1-0.2)}{500}}}=3.913$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>3.913)=0.000046$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of subscribers that would upgrade to a new cellphone at a reduced cost is significantly higher than 0.2 or 20%

6 0

4 years ago

Complete the square for the equation. 14. x2 + 4x + 5 = 0