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Anastasy [175]
3 years ago
9

Complete the square for the equation. 14. x2 + 4x + 5 = 0

Mathematics
1 answer:
andreev551 [17]3 years ago
8 0

Answer:

(x+2)^2=-1

Step-by-step explanation:

Yall have a great day!!!!!! Don't Forget to Rate my answer

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Which number has the same value as 28 tens? 28 or 280
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28 because we are talking about TENS meaning there can only be 2 digits
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A 5 hour and 25-minute flight begins at 9:40 at what time will it end
motikmotik
Your answer is 3:05.

 You must add on to 9:40. So what I did was 9 + 5 = 14.
14 - 12 = 2.
So far it's 2:40.
25 minutes + 40. = 65.
Well there are 60 minutes in an hours. So 65 would be equal to 1H and 5min.
Now take that 1 hour. Add it to 2.
3 hours. And take your 5 minutes.
There! 3:05
7 0
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What is the value of the product of -20/48 times 6 in simplified form
KATRIN_1 [288]
-20/48 x 6 =   \frac{-20}{48}    x  \frac{6}{1}

I would cancel out the 6 in the numerator and the 48 in the denominator 
Now I have <u />\frac{-20}{8}  or <u />\frac{-5}{2} reduced.

-5 ÷ 2  = -2 1/2 and that is the answer in simplest form
8 0
3 years ago
How can you find the height of 430 basketball players without adding up all the height
Ahat [919]
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3 0
3 years ago
1. Write the standard form of the line that passes through the given points. (7, -3) and (4, -8)
Sveta_85 [38]

Answer:

1. -5x+3y+44=0

2. 2x+y-2=0

3. 2x+y-4=0

Step-by-step explanation:

Standard form of a line is Ax+By+C=0.

If a line passing through two points then the equation of line is

y-y_1=m(x-x_1)

where, m is slope, i.e.,m=\dfrac{y_2-y_1}{x_2-x_1}.

1.

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)

y+3=\dfrac{-5}{-3}(x-7)

y+3=\dfrac{5}{3}(x-7)

3(y+3)=5(x-7)

3y+9=5x-35

-5x+3y+9+35=0

-5x+3y+44=0

Therefore, the required equation is -5x+3y+44=0.

2.

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to 2 x + y =-5.

Slope of the line : m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

y-2=-2(x-0)

y-2=-2x

2x+y-2=0

Therefore, the required equation is 2x+y-2=0.

3.

We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to 2x + y =-5.

From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).

Equation of line is

y-0=-2(x-2)

y=-2x+4

2x+y-4=0

Therefore, the required equation is 2x+y-4=0.

5 0
3 years ago
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