Answer:
153.94
Step-by-step explanation:
AB=πr2=π·72≈153.93804
Pls. see attachment.
We need to solve for the angles of the smaller triangle in
order to solve for the angle of the larger triangle which would help us solve
the missing measurement of a side.
Given:
51 degrees.
Cut the triangle into two equal sides and it forms a right
triangle. All interior angles of a triangle sums up to 180 degrees.
180 – 51 – 90 = 39 degrees
39 degrees * 2 = 78 degrees.
Angle Q is 78 degrees.
In the bigger triangle, 4.3 is the hypotenuse. We need to
solve for the measurement of the long leg which is the opposite of the 78
degree angle.
We will use the formula:
Sine theta = opposite / hypotenuse
Sin(78 deg) = opposite / 4.3
Sin(78 deg) * 4.3 = opposite
4.21 = opposite. This is also the height of the triangle.
Area of a triangle = ½ * base * height
A = ½ * 3units * 4.21units
A = 6.315 square units.
Answer:
3 2/3 pint
Step-by-step explanation:
First break down the mixed number to divide (into 7 and 1/3)
7 divided by 2 is 3.5 (Convert 3.5 to sixths)
1/3 divided by two is 1/6
1/6 + 3 3/6= 3 4/6 OR 3 2/3
Hope this helps! :)
<u>Given</u><u> </u><u>Information</u><u> </u><u>:</u><u>-</u>
⠀
- A polygon with 10 sides ( Decagon )
⠀
<u>To</u><u> </u><u>Find</u><u> </u><u>:</u><u>-</u>
⠀
- The value of one of the exterior angles
⠀
<u>Formula</u><u> </u><u>Used</u><u> </u><u>:</u><u>-</u>
⠀
![\qquad \diamond \: \underline{ \boxed{ \pink{ \sf Exterior ~angle = \dfrac {360^\circ}{no. ~of~sides}}}} \: \star](https://tex.z-dn.net/?f=%20%5Cqquad%20%5Cdiamond%20%5C%3A%20%20%5Cunderline%7B%20%5Cboxed%7B%20%5Cpink%7B%20%5Csf%20Exterior%20~angle%20%3D%20%5Cdfrac%20%7B360%5E%5Ccirc%7D%7Bno.%20~of~sides%7D%7D%7D%7D%20%5C%3A%20%20%5Cstar)
⠀
<u>Solution</u><u> </u><u>:</u><u>-</u>
⠀
Putting the given values, we get,
⠀
![\sf \dashrightarrow Exterior ~angle = \dfrac{360 ^\circ}{10} \: \: \\ \\ \\ \sf \dashrightarrow Exterior ~angle = \frac{36 \cancel{0}^\circ}{ \cancel{10}} \: \: \\ \\ \\ \sf \dashrightarrow Exterior ~angle = \underline{ \boxed{ \frak{ \red{36^\circ}}}} \: \star \\ \\](https://tex.z-dn.net/?f=%5Csf%20%5Cdashrightarrow%20Exterior%20~angle%20%3D%20%20%5Cdfrac%7B360%20%20%5E%5Ccirc%7D%7B10%7D%20%5C%3A%20%20%5C%3A%20%20%20%5C%5C%20%20%5C%5C%20%20%5C%5C%20%5Csf%20%5Cdashrightarrow%20Exterior%20~angle%20%3D%20%20%5Cfrac%7B36%20%5Ccancel%7B0%7D%5E%5Ccirc%7D%7B%20%5Ccancel%7B10%7D%7D%20%5C%3A%20%20%5C%3A%20%20%20%5C%5C%20%20%5C%5C%20%20%5C%5C%20%5Csf%20%5Cdashrightarrow%20Exterior%20~angle%20%3D%20%20%5Cunderline%7B%20%5Cboxed%7B%20%5Cfrak%7B%20%5Cred%7B36%5E%5Ccirc%7D%7D%7D%7D%20%5C%3A%20%5Cstar%20%5C%5C%20%20%5C%5C%20)
Thus, the value of the exterior angles of a Decagon is 36°.
⠀
![\underline{ \rule{227pt}{2pt}} \\ \\](https://tex.z-dn.net/?f=%20%5Cunderline%7B%20%5Crule%7B227pt%7D%7B2pt%7D%7D%20%5C%5C%20%20%5C%5C%20)
Answer:
(0,0)
Step-by-step explanation:
Y = 2x is a <u>proportional</u> relationship because it follows the form y = kx, where k = constant of proportionality. Proportional relationships intersect the y-axis at (0,0), thus having a y-intercept of 0, but we usually don't write the 0.
Given the information above, y = 2x intersects the y-axis at (0,0), the origin.
Have a lovely rest of your day/night, and good luck with your assignments! ♡