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3 years ago

Help meh pllllllllllllllzzzzzzzzz

Mathematics

1 answer:

juin [17]3 years ago

7 0

Answer:

$\frac{2,000}{365}$ = $\frac{x}{500}$

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3 years ago

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3 years ago

Divide the fractions and simplify the answer . 1/2 ÷ 5/8

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3 years ago

Two number cubes are rolled sequentially. What is the probability that the first number cube shows a five and the other number c

nexus9112 [7]

The probability of first number cube shows a five and the other number cube shows an even number is $\frac{1}{12}$ .

Solution:

Two cubes are rolled sequentially.

Sample space when two dies are rolled

$=\left\{\begin{array}{l}{(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)} \\{(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)} \\{(3,1), 3(, 2),(3,3),(3,4),(3,5),(3,6)} \\{(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)} \\{(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)} \\{(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}\end{array}\right\}$

Number of sample space = 36

Even numbers getting when two cubes rolled are 2, 4, 6.

First number cube shows a five and the other number cube shows an even number = {(5, 2), (5, 4), (5 6)}

Number of first number cube shows a five and the other number cube shows an even number = 3

Probability of first number cube shows a five and the other number cube shows an even number

$=\frac{\text{Number of outcomes}}{\text{Total number of sample space}}$

$$=\frac{3}{36}$

$$=\frac{1}{12}$

Hence, the probability of first number cube shows a five and the other number cube shows an even number is $\frac{1}{12}$ .

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3 years ago