Answer:
Step-by-step explanation:
We need to find the conditional probability P( T1 < s|N(t)=1 ) for all s ≥ 0
P( time of the first person's arrival < s till time t exactly 1 person has arrived )
= P( time of the first person's arrival < s, till time t exactly 1 person has arrived ) / P(exactly 1 person has arrived till time t )
{ As till time t, we know that exactly 1 person has arrived, thus relevant values of s : 0 < s < t }
P( time of the first person arrival < s, till time t exactly 1 person has arrived ) / P(exactly 1 person has arrived till time t )
= P( exactly 1 person has arrived till time s )/ P(exactly 1 person has arrived till time t )
P(exactly x person has arrived till time t ) ~ Poisson(kt) where k = lambda
Therefore,
P(exactly 1 person has arrived till time s )/ P(exactly 1 person has arrived till time t )
= [ kse-ks/1! ] / [ kte-kt/1! ]
= (s/t)e-k(s-t)
how many students got 90 or less = 14
how many students got more than 90 = 11
3 more students got 90 or less so answers is D. 3
please mark brainliest
I think the answer is choosing an odd number
Answer:
8x + 6 + 4 = 3x - (2x + 4)
Step-by-step explanation:
When Gio applies the distributive property, the equation above is the result. Naturally, I look at the 1st parenthesis I see and start the 1st distributive property there first. The 2nd distributive property would be the other parenthesis where you multiply by -1, so you would get 8x + 6 + 4 = 3x - 2x - 4
Answer:
1/6
Step-by-step explanation:
1/2/3 is a sixth of an apple that all 3 people equally shared.
