Question

Determine where the real zeros of f(x)=x^4-2x^3+x-2 are located.

Answer 1

Answer:

a. at -1 & 2

Step-by-step explanation:

The given function is

$f(x)=x^4-2x^3+x-2$.

Equate the function to zero.

$x^4-2x^3+x-2=0$.

Factor by grouping;

$x^3(x-2)+1(x-2)=0$

Factor further;

$(x-2)(x^3+1)=0$

Apply the zero product property;

$(x-2)=0,(x^3+1)=0$

Solve for x;

$x=2,x^3=-1$

$\Rightarrow x=2,x=\sqrt[3]{-1}$

$\therefore x=2,x=-1$

Answer 2

Answer:

its a i just took quiz

Step-by-step explanation: