All categories

3 years ago

SOMEONE PLEASE HELP ME WITH THIS ILL GIVE YOU BRAINLY IF YOU GET IT RIGHT PLEASE!!!!!

Computers and Technology

2 answers:

-Dominant- [34]3 years ago

7 0

Answer:

Supply and demand can affect job stability since if your supply is high whilst your demand is low, you'll make less money from stocks and will be paying for supplies which aren't being used or sold and therefore will be losing money and profits, meaning that the jobs stability will be lowered due to lack of pay, resulting in a cut of workers

zepelin [54]3 years ago

3 0

Answer:

Supply and demand affects the labor market just like any other market. ... On the flip side if demand for a job increases while supply stays stable then job stability gets higher and income could get higher as employers are willing to pay more

You might be interested in

The New option is found in the ...............tab.

morpeh [17]

in your notes books and in your vopy

3 0

3 years ago

Read 2 more answers

Output each floating-point value with two digits after the decimal point, which can be achieved as follows:

sdas [7]

Answer:

The modified program in Python is as follows:

import math

paint_colors = {'red': 35,'blue': 25,'green': 23}

wall_height = int(input('Enter wall height (feet):\n'))

wall_width = int(input('Enter wall width (feet):\n'))

area = wall_height*wall_width

print('Wall area:',area,'square feet')

paint_needed = area/350.0

print('Paint needed: {:.2f} gallons'.format(paint_needed))

print('Cans needed:',round(paint_needed),'can(s)')

color = input("Choose a color to paint the wall: ")

print("Cost of purchasing", color, "paint: $",paint_colors[color])

Explanation:

The italicized are given from the question [unchanged]

import math

paint_colors = {'red': 35,'blue': 25,'green': 23}

wall_height = int(input('Enter wall height (feet):\n'))

This gets input for width

wall_width = int(input('Enter wall width (feet):\n'))

Calculate the wall area

area = wall_height*wall_width

Print the calculated wall area

print('Wall area:',area,'square feet')

Calculate the amount of paint needed

paint_needed = area/350.0

Print the amount of paint needed to 2 decimal places

print('Paint needed: {:.2f} gallons'.format(paint_needed))

Print the amount of can needed to nearest integer

print('Cans needed:',round(paint_needed),'can(s)')

Prompt user for color of paint [here, we assume the user input is correct]

color = input("Choose a color to paint the wall: ")

Prints the corresponding amount for the color

print("Cost of purchasing", color, "paint: $",paint_colors[color])

3 0

3 years ago

I need Help!! 4. Explain the importance of including negative space as part of a design.

vova2212 [387]

Negative space is the space between, within and surrounding an object in an image. The positive space is the focus of the image, the object itself, but the negative space is just as important. It shares edges with the positive space, defining the outline of the object and creating proportion

5 0

3 years ago

19. Fair use applies to which of the following situations?

MatroZZZ [7]

I think it’s B if not it’s D both are similar

4 0

3 years ago

Array Challenge Have the function ArrayChallenge (arr) take the array of numbers stored in arr and return the string true if any

vampirchik [111]

Answer:

The code is given as follows,

Explanation:

Code:

#include <stdio.h>

#include <string.h>

int n; //to store size of array

char* ArrayChallenge(int arr[]) //function returns string true or false

{

int i, j;

int sum = 0;

for(i = 0; i < n; i++)

{

sum = sum + arr[i]; //count sum

}

for(i = 0; i < n; i++)

{

for(j = i+1; j < n; j++) //loop for every two elements in array

{

if(arr[i]*arr[j] > 2*sum) //check if proudct of two elements > 2 times sum

{

printf("\n%d x %d = %d, 2xSum = %d\n", arr[i], arr[j], arr[i]*arr[j], 2*sum);

return "true"; //If proudct of two elements > 2 times sum. return true

}

return "false"; // If proudct of two elements < 2 times sum. return false

}

int main()

{

printf("\nEnter size of array: ");

scanf("%d", &n); //read size of array

int A[n]; //array of size n

printf("\nEnter array elements: ");

int i;

for(i = 0; i < n; i++)

{

scanf("%d", &A[i]); //read array from stdin

}

printf("%s\n",ArrayChallenge(A)); //ccall function and print answer

return 0;

}

6 0

3 years ago