The center of mass is defined as a point on the straight line between two objects with masses m1 and m2 such that L1 / L2 = M2 /
M1 . What are the coordinates of the center of mass?
1 answer:
We can represent the problem as shown in the attached drawing
L1=x1
L2=x2
L=x------------distance of the center of mass
we have that
L1/L2=m2/m1------------------> L1*m1=L2*m2------------->m2=L1*m1/L2
moment = Md
the moment about O is defined to be
m1*L1+m2*L2=(m1+m2)*L
L=(m1*L1+m2*L2)/(m1+m2)
m1*L1+m2*L2=2*m1*L1--------remember-------------------->L1*m1=L2*m2
L=(2*m1*L1)/(m1+L1*m1/L2)
L=(2*m1*L1)/(m1*L2+L1*m1)/L2=(2*m1*L1)*L2/(L2*m1+L1*m1)
L=(2*L1*L2)/(L1+L2)
the coordinates of the center of mass are (L,0)
You might be interested in
Premium rates are usually for premium per fixed face value. Jade's annual premium for a 10 year policy is given by Option b: $1,202
<h3>How to calculate the total annual premium for $x ?</h3>If its given that the annual premium is $p per $y face value, then we can calculate the annual premium for $1 face value and then use it to calculate annual premium for $x.
Using proportions, we get:
For given case, from the tables, we see that for age 34, and 10 year life insurance for female gender , there is annual premium of 6.01 per $1000 face value.
Thus, we have p = 6.01, y = 1000
Since Jade wants to buy Life insurance for $200,000, thus, x = $200,000
Putting it in the above derived formula, we get:
Thus, Jade's annual premium for a 10 year policy is given by Option b: $1,202
Learn more about calculating annual premium cost here: