Answer:
The largest integer is 29.
Step-by-step explanation:
Let the consecutive positive integers are x, x+1 and x+2.
The square of sum of squares of three consecutive positive integers is 2354 such that,
It is a quadratic equation whose solution is given by :
x = 27 and x = -29
First positive integer = 27
Second positive integer = 27+1 = 28
Third positive integer = 27+2 = 29
Hence, the largest integer is 29.
Answer:
Length of the boxes are 17 in, 35 in, 17 in.
Step-by-step explanation:
The given question is incomplete: please find the complete question in the attachment.
A). From Box - (1)
Area of the box = 289 in.²
Expression that denotes the area of the box = 36x² - 12x + 1
So, 36x²- 12x + 1 = 289
(6x)² - 2(6)x + (1)² = (17)²
(6x - 1)² = (17)² [ Since (a² - 2ab + b²) = (a - b)²]
Given box is a square having sides = (6x - 1) in.
∵ (6x - 1)² = 17
⇒ 6x = 18
⇒ x = = 3
Now length of the sides = (6x - 1) = 17 in.
B) Box - (2)
Similarly, 25x²- 50x + 25 = 1225
(25x² - 50x + 25) = (35)²
(5x - 5)² = (35)²
5(x - 1) = 35 ⇒ x = 8
Here length of one side of the box is 5(x - 1) = 5(8 - 1) = 35in.
C). Box - (3)
49x² - 56x + 16 = 289
(7x)² - 2×(7x)(4) + 4²= (17)²
(7x - 4)² = (17)²
Length of each side = (7x - 4) in.
From, (7x - 4)² = (17)²
7x - 4 = 17
⇒ x =
⇒ x = 3
Therefore, length of each side of the box = (7x - 4) = 17 in.
