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3 years ago

I will give you that Brainly thing if it’s right plzz

Mathematics

2 answers:

shutvik [7]3 years ago

8 0

Answer:

Step-by-step explanation:

kkurt [141]3 years ago

3 0

Answer:

idc if its wrong but i think it is 21 or 420

Step-by-step explanation:

You might be interested in

The three angles in a triangle are in the ratio 3:5:7. Find the largest angle in the triangle?

Rzqust [24]

Answer: The largest angle is 7x

Step-by-step explanation:

Their sum is 180, so

3x + 5x + 7x = 180

5x = 180 --> x = 12

The largest angle is 7x, which is 7(12) = 84

7 0

2 years ago

A car used 5 2/3 gallons of fuel on a 3 hour trip. How many gallons were used each hour?

mr_godi [17]

Answer:

2. 1 8/9 gallons

Step-by-step explanation:

5 2/3 divided by 3

5.66666667/3 = 1.88888889

.88888889 = 8/9

1 + 8/9 = 1 8/9

5 0

2 years ago

In your job at a restaurant, you made a 12-cup pot of coffee at 7:20 a.m. By 7:40 a.m., you had served it all and had to make an

Anarel [89]

Answer:

36 cups

Step-by-step explanation:

every 20 minutes you make 12 cups. 20×3=60, which is 1 hour. You will meed to make 3 pots of coffee that are 12 cups each, 3×12=36

3 0

2 years ago

Read 2 more answers

You could win a giant jar of M&Ms, if only you could guess how many are in the jar. You find a smallerjar such that the gian

sleet_krkn [62]

Answer:

There are 7360 M&Ms in larger jar.

Step-by-step explanation:

We are given the following in the question:

A giant jar is such that it is exactly four times times the smaller jar in dimensions.

If r and h is the radius and height of the cylindrical jar respectively, then the dimensions of the larger are:

$R = 4r\\H=4h$

Number of M&Ms in smaller jar = 115

Volume of smaller jar =

$v = \dfrac{1}{3}\pi r^2 h$

Volume of larger jar =

$V =\dfrac{1}{3}\pi R^2 H=\dfrac{64}{3}\pi r^2 h$

Number of M&Ms in larger jar:

$v = \dfrac{1}{3}\pi r^2 h\rightarrow 115\\\\V=\dfrac{64}{3}\pi r^2 h\rightarrow 115\times 64\\\\V=\dfrac{64}{3}\pi r^2 h\rightarrow 7360$

Thus, there are 7360 M&Ms in larger jar.

6 0

3 years ago

The population of Henderson City was 3,381,000 in 1994, and is growing at an annual rate 1.8%

liq [111]

<h2>In the year 2000, population will be 3,762,979 approximately. Population will double by the year 2033.</h2>

Step-by-step explanation:

Given that the population grows every year at the same rate( 1.8% ), we can model the population similar to a compound Interest problem.

From 1994, every subsequent year the new population is obtained by multiplying the previous years' population by $\frac{100+1.8}{100}$ = $\frac{101.8}{100}$ .

So, the population in the year t can be given by $P(t)=3,381,000\textrm{x}(\frac{101.8}{100})^{(t-1994)}$

Population in the year 2000 = $3,381,000\textrm{x}(\frac{101.8}{100})^{6}$ = $3,762,979.38$

Population in year 2000 = 3,762,979

Let us assume population doubles by year $y$ .

$2\textrm{x}(3,381,000)=(3,381,000)\textrm{x}(\frac{101.8}{100})^{(y-1994)}$

$log_{10}2=(y-1994)log_{10}(\frac{101.8}{100})$

$y-1994=\frac{log_{10}2}{log_{10}1.018}=38.8537$

$y$ ≈ $2033$

∴ By 2033, the population doubles.

4 0

3 years ago