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3 years ago

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NEED HELP 10 POINTS

1 answer:

leonid [27]3 years ago

6 0

48.8 megabytes. When the download is 17.5% complete, have been downloaded 48.8 megabytes.

The key to solve this problem is using the rule of three.

If 279Mb -------------> 100%

x <------------- 17.5%

x = [(279 megabytes)(17.5)]/100

x = 48.825 megabytes

Round to the nearest tenth 48.8 megabytes.

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Ashton read 12 pages on Friday. He read 3 times as many pages on Saturday, and 14 more pages on Sunday.How many more pages did A

weeeeeb [17]

Answer:

Ashton read 62 pages over the three days

Step-by-step explanation:

Given;

Ashton read 12 pages on Friday

He read 3 times as many pages on Saturday = 3 x 12 pages = 36 pages

He read 14 more pages on Sunday

The total number of pages read Ashton over the three days can be calculated as follows;

Total pages read by Ashton = 12 pages + 36 pages + 14 pages

Total pages read by Ashton = 62 pages

Therefore, Ashton read 62 pages over the three days

3 0

3 years ago

How do you solve chords and arcs in geometry?

yawa3891 [41]

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2. The relationship between equality of the measures of chords and equality of the measures of their corresponding minor arcs.

3. A diameter that is perpendicular to a chord.

4. In a circle, the relationship between two chords being equal in measure and being equidistant.

5. A circle with two minor arcs equal in measure

6. A circle with a diameter perpendicular to a chord.

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5 0

3 years ago

Posing A(-4,2) is reflected over the line x= 3 to create the point A’. What are the coordinates of A

lilavasa [31]

The coordinate of A would be (10,2)

5 0

3 years ago

Write the equation log243(81) =4/5

lawyer [7]

Step-by-step explanation:

log243(81)=4/5

81=243^4/5

Option B

3 0

3 years ago

Can you help me with my math questions

GrogVix [38]

$p^2+2(7)p+7^2=(p+7)^2$

Justification:

Given: $p^2+14p+49$

Split the middle term;

$=p^2+7p+7p+49$

Factor:

$=p(p+7)+7(p+7)$

$=(p+7)(p+7)$

$=(p+7)^2$

QUESTION 3a

The given expression for the area of the rectangle is $36x^2-12x+1$ .

This is equal to the indicated area which is $289\;in^2$

This implies that

$36x^2-12x+1=289$

$\Rightarrow (6x-1)^2=289$

$\Rightarrow (6x-1)(6x-1)=289$

$\Rightarrow l=(6x-1),w=(6x-1)$

This implies that, the dimensions of the rectangle are equal;

Using the square root method, we obtain

$\Rightarrow (6x-1)=\pm \sqrt{289}$

$\Rightarrow (6x-1)=\pm 17$

$\Rightarrow 6x=1\pm 17$

$\Rightarrow 6x=18 \:or\:6x=-16$

$\Rightarrow x=3 \:or\:x=-\frac{2}{3}$

We discard the negative value.

The side length of this rectangle is

$\Rightarrow l=(6(3)-1)=17,w=6(3)-1=17$

QUESTION 3b

The given expression for the area of the rectangle is $25x^2-50x+25$ .

This is equal to the indicated area which is $1225\;in^2$

This implies that

$25x^2-50x+25=1225$

$25(x^2-2x+1)=1225$

$(5(x-1))^2=35^2$

$5(x-1)5(x-1)=49$

$\Rightarrow l=5(x-1),w=5(x-1)$

This implies that, the dimensions of the rectangle are equal;

Using the square root method, we obtain

$\Rightarrow 5(x-1)=\pm \sqrt{1225}$

$\Rightarrow 5(x-1)=\pm 35$

$\Rightarrow x=1\pm 7$

$\Rightarrow x=8 \:or\:x=-6$

We discard the negative value.

The side length of this rectangle is

$\Rightarrow l=5(8-1)=35,w=5(8-1)=35$

QUESTION 3c

The given expression for the area of the rectangle is $49x^2-56x+16$ .

This is equal to the indicated area which is $289\;in^2$

This implies that

$49x^2-56x+16=289$

$(7x-4)^2=289$

$(7x-4)(7x-4)=289$

$\Rightarrow l=(7x-4),w=(7x-4)$

Applying the laws of indices gives;

$(7x-4)^2=17^2$

This implies that;

$7x-4=17$

$7x=21$

$x=3in.$

The side length of this rectangle is

$\Rightarrow l=7(3)-4=17\:in.,w=7(3)-4=17\:in.$

Dont forget that the square is also a rectangle.

5 0

3 years ago

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