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3 years ago

Hi guys... I'm a foreigner... I've completed my high Schools...nd I'd like to know what should I do to get into MIT? Help me

1 answer:

6 0

Answer:A strong academic foundation in high school contributes to your own development, improves your odds of getting into MIT, and helps you make the most of the Institute when you’re here.

Step-by-step explanation:

high school years include the following:

One year of high school physics

One year of high school chemistry

One year of high school biology

Math, through calculus

Two years of a foreign language

Four years of English

Two years of history and/or social sciences

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Can somebody help plz

Evgen [1.6K]

Answer:

(3,2)

Step-by-step explanation:

the other three ordered pairs do not lie in the shaded region

6 0

3 years ago

Read 2 more answers

Identify the center and the radius of a circle that has a diameter with endpoints at (−5, 9) and (3, 5)

marusya05 [52]

Check the picture below, so the circle looks more or less like that one.

well, the center of it is simply the Midpoint of those two points, and its radius is simply half-the-distance between them.

$~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-5}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{5}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ 3 -5}{2}~~~ ,~~~ \cfrac{ 5 + 9}{2} \right)\implies \left( \cfrac{-2}{2}~~,~~\cfrac{14}{2} \right)\implies \stackrel{center}{(-1~~,~~7)} \\\\[-0.35em] ~\dotfill$

$~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-5}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[3 - (-5)]^2 + [5 - 9]^2}\implies d=\sqrt{(3+5)^2+(-4)^2} \\\\\\ d=\sqrt{8^2+16}\implies d=\sqrt{80}\implies d=4\sqrt{5}~\hfill \stackrel{\textit{half the diameter}}{\cfrac{4\sqrt{5}}{2}\implies \underset{radius}{2\sqrt{5}}}$

8 0

2 years ago

Solve,y=5 and 3x +2y=-5

Allushta [10]

Answer:

x = -5

Step-by-step explanation:

I) Substitute:

3x + 2y = -5

3x + 2(5) = -5

3x + 10 = -5

II) Solve:

3x + 10 = -5

3x = -15 (Subtract 10 from both sides)

x = -5 (Divide both sides by 3)

5 0

2 years ago

Read 2 more answers

Which reason completes the proof below?

sergeinik [125]

Observe the figure given.

Given: ABCD is a parallelogram.

To prove: ABCD is a rhombus

Statement

1. ABCD is a parallelogram. AC bisects $\angle BCD, \angle BAD$ .

Reason: Given

2. $\angle 1 \cong \angle 2, \angle 3 \cong \angle 4$

Reason: Definition of an angle bisector

3. $AC \cong AC$

Reason: Reflexive property of congruence

4. $\Delta ABC \cong \Delta ADC$

Reason: ASA Postulate

5. $AB \cong AD, BC \cong DC$

Reason: corresponding parts of congruent triangles are equal.

6. $AB \cong CD, BC \cong AD$

Reason: Opposite sides of the parallelogram are congruent.

7. $AB \cong AD \cong BC \cong CD$

Reason: Transitive property of congruence

8. ABCD is a rhombus

Reason: Definition of rhombus

4 0

3 years ago

The value of x varies directly with y, and whenX= 2/3, y = 6. Find the value of y when x = 10-24A.y=9B.y=4C. y=93D.y=1

uysha [10]

Problem

Solution

for this case we know that when x =2/3 , y= 6

$10\frac{1}{3}=\frac{10\cdot3+1}{3}=\frac{30+1}{3}=\frac{31}{3}$

Then we want to find the value of y= ? when x= 10 1/3 = 31/3 and we can do this:

6/(2/3) = y/(31/3)

$\frac{6}{\frac{2}{3}}=\frac{y}{\frac{31}{3}}$ $y=\frac{31}{3}\cdot\frac{6}{\frac{2}{3}}=\frac{31}{3}\cdot\frac{3}{2}\cdot\frac{6}{1}=\frac{31\cdot3\cdot6}{3\cdot2\cdot1}=93$

And solving for y we got:

y = (3/2) * 6 * (31/3) = 31*3 = 93

C. y= 93

7 0

1 year ago