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Ivenika [448]
3 years ago
12

Which could the coordinates of the vertices of the following isosceles trapezoid centered in the origin, with base 2a and OR=c?

Mathematics
1 answer:
V125BC [204]3 years ago
7 0

Answer:

Option (3) is correct.

The coordinates of the vertices of the given isosceles trapezoid centered in the origin, with base 2a and OR=c are,

S(-a, 0) , Z(a, 0) , T(-b, c) and W(b, c)

Step-by-step explanation:

Given an isosceles trapezoid centered in the origin, with base 2a and OR = c.

We have to find the coordinates of vertices of the given isosceles trapezoid.

Since  O is at center then , coordinates of O (0,0).

And base SZ given to be 2a .

So SO = OZ

SO + OZ = SZ ⇒ 2 (SO) = 2a ⇒SO = a

Since point S lies in second quadrant and x coordinates in second quadrant are negative, thus Coordinate of S is (-a, 0)

and Z lies in first quadrant , both x and y are positive,

So, coordinate of Z is (a, 0)

given OR = c so R lies on y axis , so R has coordinate (0,c)

Since point T lies in second quadrant and x coordinates in second quadrant are negative, thus Coordinate of T is of the form (-x, c)

also, W lies in first quadrant , both x and y are positive. Thus, coordinate of W is of the form  (x,c)

When we compare from the given options, we get possible value of x is b,

Thus, the coordinates of the vertices of the given isosceles trapezoid centered in the origin, with base 2a and OR=c are,

S(-a, 0) , Z(a, 0) , T(-b, c) and W(b, c)

Option (3) is correct.

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a. $45.54; b. $51.42; c. See below

Step-by-step explanation:

a. 193 min

        Service charge = $40.00

1st 100 min @ 0.021 =      2.10

Next 93 min @0.037 = <u>    3.44 </u>

                        Total =  $45.54

b. 317 min

          Service charge = $40.00

  1st 100 min @ 0.021 =      2.10

2nd 100 min @ 0.037 =     3.70

        117 min @ 0.048 =   <u>   5.62</u>

                          Total =   $51.42

c. Piecewise function

The charge is  

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which we can write like this:

f(t) =\begin{cases}40.00 + 0.021t & t \leq 100\\42.10 + 0.037(t-100) & 100 < t \leq200\\45.80 + 0.048(t-200) & t > 200\end{cases}

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