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Margarita [4]
4 years ago
6

How would you solve a problem in time travel if you you departing at 1:10 PM EST and arriving at 8:29 PM PST.

Mathematics
1 answer:
In-s [12.5K]4 years ago
5 0

Answer:

you would figure out the time in either pst or est and find out the time

Step-by-step explanation:

Example=EST

1:10 PM

PST:8:29 PM=11:29PM

SO time spent= 3 hours

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The value of 10 small 4
professor190 [17]

Answer:

I'm guessing you mean 10^4 = ?

Well, that equals 10 * 10 * 10 * 10

which equals 10,000

Step-by-step explanation:

8 0
3 years ago
Triple beam balanceeqfwrgthyjukjyrhtegfdasfgrethyjuyjuthrgbgnheiuenyrbtwev
Leto [7]

Answer:

the quadruple story of wwfvhjvddghkkyffxsedfvf22223

8 0
4 years ago
Read 2 more answers
Factor Completely:<br> 49c 2 +70cd+25d 2 = ? <br> HURRY I NEED HELP ASAP
omeli [17]

Answer:

(7c + 5d)²

Step-by-step explanation:

In order to factor a quadratic equation, we need to look at the coefficients of all the terms.  In this case the following quadratic:

49c² + 70cd + 25d², has an 'a' = 49, 'b' = 70 and 'c' = 25.

When we take the √49 = 7 and the √25 = 5, we can see that when we multiply 7 x 5 = 35 and 35 + 35 = 70, so we know that our two equations will be the same: (7c + 5d)

Using the FOIL (forward, outside, inside, last) method, we can check our answer:

(7c + 5d)(7c + 5d) = 49c² + 35cd + 35cd + 25d² or 49c² + 70cd + 25d²

3 0
3 years ago
An equilateral triangle with sides of length 6 is inscribed in a circle. What is the diameter of the Circle?
azamat

Answer:

The diameter is 6.92 unit.

Step-by-step explanation:

Given : An equilateral triangle with sides of length 6 is inscribed in a circle.

To find : What is the diameter of the Circle?

Solution :

First we picture the situation.

Refer the attached figure below.

We that the angles of equilateral triangle is 60 degrees.

Then, we divide the triangle into two parts to solve the radius.

As,

∠ACD is 60°

\angle OCD=\frac{\angle ACD}{2}

\angle OCD=\frac{60}{2}=30^\circ

In triangle OCD,

\cos 30^\circ= \frac{CD}{OC}

\cos 30^\circ= \frac{CD}{OC}

\frac{\sqrt{3}}{2}=\frac{3}{r}

r=\frac{3\times 2}{\sqrt{3}}

r=2\sqrt{3}

r=3.4641

Diameter = 2r=2(3.4641)=6.92 unit.

Therefore, The diameter is 6.92 unit.

7 0
3 years ago
Read 2 more answers
What is the pH of a buffer that is 0.6 M HF and 0.2 M NaF? The Ka of HF is 6.8 Ã 10â4. What is the pH of a buffer that is:______
ollegr [7]

Answer:

The correct option is  d

Step-by-step explanation:

From the question we are told that

   The concentration of  HF  is  [HF] =  0.6 M

   The concentration of  NaF  is  [NaF ] =  0.2 M

   The Ka of  HF  is  K_a  =  6.8 *10^{-4} \

Generally HF(Hydrogen fluoride )  is ionized as follows  

      HF_{(aq)} + H_2 O _{(l)}   \rightleftharpoons  H_3O^+ _{(aq) } + F^- _{(aq)}  

Generally NaF(Sodium fluoride )  is ionized as follows  

       NaF_{(aq)} + H_2 O _{(l)}   \rightleftharpoons  Na^+ _{(aq) } + F^- _{(aq)}  

Generally the from Henderson-Hasselbalch equation the pH of the buffer is mathematically represented as

       pH  =  pKa  + log [\frac{[NaF ]}{HF} ]

=>     pH  =  -log(K_a)  + log [\frac{[NaF ]}{HF} ]

=>     pH  =  -log(6.8 *10^{-4})  + log [\frac{[0.2 ]}{0.6} ]

=>    pH  =  2.69

5 0
3 years ago
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