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dolphi86 [110]
2 years ago
5

PLEASE HELP! I’m stuck on number 7 and 8! I’ll mark brainliest for best answer

Mathematics
2 answers:
alexandr1967 [171]2 years ago
8 0
Question 7
-5/14

Question 8
17/3
kolbaska11 [484]2 years ago
7 0

Answer:

7.) -5/14

8.) 2 1/3

Step-by-step explanation:

You might be interested in
If the width of a rectangle is(x + 5) cm and its perimeter is (10x + 26) cm.
zaharov [31]

Answer:

10x + 26 = 2x + 58

10x = 58-26

10x = 32

X = 3.2

I think??

3 0
3 years ago
54 miles is 18% of how many miles?
riadik2000 [5.3K]

Answer:

(set up a ratio)

54/x = 18/100

(cross multiply)

18x = 5400

(solve for x)

x = 300 miles

Step-by-step explanation:

6 0
3 years ago
For parts a and bâ, use technology to estimate the following. âa) The critical value of t for a 90â% confidence interval with df
rjkz [21]

Answer:

a) For the 90% confidence interval the value of \alpha=1-0.9=0.1 and \alpha/2=0.05, with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:

t_{\alpha/2} =\pm 2.35

b) For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:

t_{\alpha/2} =\pm 2.62

Step-by-step explanation:

Previous concepts

The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".

The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.  

The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."

Solution to the problem

Part a

For the 90% confidence interval the value of \alpha=1-0.9=0.1 and \alpha/2=0.05, with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:

t_{\alpha/2} =\pm 2.35

Part b

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:

t_{\alpha/2} =\pm 2.62

3 0
3 years ago
My maths teacher set me this as work. And never told me what to do
Sergeu [11.5K]
<h3>Area of shape P = 12 square cm</h3>

Explanation:

Shape P is a triangle with the base of 4 units across the horizontal portion up top.

The height of the triangle is 6 units. Count the spaces down the middle of the triangle and you should get 6 spaces.

Area = base*height/2

Area = 4*6/2

Area = 24/2

Area = 12 square cm.

4 0
2 years ago
PLS HELP ME RN I AM FAILING AND NEED HELP ITS PYTHAGOREAN THEOREM
jekas [21]

Answer:

9.89949 or 9.9

Step-by-step explanation:

7^2 + 7^2 = c^2

49+49=98

square root of 98 = 9.89949

5 0
2 years ago
Read 2 more answers
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