Answer:
Step-by-step explanation:
<em>(17).</em> g(x) = x³ + 4x
f(x) = 4x + 1
( f × g )( x ) = ( x³ + 4x )( 4x + 1 ) = <em>4 </em>
<em> + x³ + 16x² + 4x</em>
<em>(19).</em> f(t) = 4t - 4
g(t) = t - 2
( 4f + 3g )( t ) = 4(4t - 4) + 3(t - 2) = 16t - 16 + 3t - 6 = <em>19t - 22</em>
<em>(21).</em> h(t) = t + 3
g(t) = 4t + 1
h(t - 2) + g(t - 2) = ( t - 2 ) + 3 + 4( t - 2 ) + 1 = t + 4t - 2 + 3 - 8 + 1 = <em>5t - 6</em>
Answer:
x=14
y=12
Step-by-step explanation:
so you add 3 plus 9 and 2 plus 4 with 8 and you should get x- 14 and y= 12
Hope this helps
Answer:
doesn't it give you the angles for each letter? If that is the case then it would be 33
Step-by-step explanation:
May I have brainliest please? :)
Answer:
The domain of the function is all real values of x, except 
and 
Step-by-step explanation:
We are given the following function:
It's a fraction, so the domain is all the real values except those in which the denominator is 0.
Denominator:
Quadratic equation with 
Using bhaskara, the denominator is 0 for these following values of x:
The domain of the function is all real values of x, except and
The image is answer.................
