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Readme [11.4K]
3 years ago
7

There are 80 sixth graders at Wilson Middle School. Only 70% of the sixth graders will attend the morning assembly. How many six

th graders will be at the morning assembly?
Mathematics
2 answers:
Nuetrik [128]3 years ago
6 0

The answer is 56 because

Recall that 70% is , and  is 0.70.


To find the number of sixth graders who will attend the morning assembly, multiply 80 by , or 0.70.




So, 56 sixth grade students will attend the morning assembly.[?][?][?][?][?][?][?][?]


zysi [14]3 years ago
4 0
1 student will attend the assembly in the morning
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Solve the equation<br> 56 ÷ (-8)= ?
Hunter-Best [27]

Answer:

-7

Step-by-step explanation:

Because for dividing one positive and one negative number, the rule is that the answer is going to be negative. So, what you can do is just do 56÷8 which equals 7 then add the negative sign to make it -7.

3 0
3 years ago
A freezer can be bought on hire purchase by making a desposiy of 15% of the cash price which is $2975 the interest which is 20%
Liono4ka [1.6K]

Answer: See explanation

Step-by-step explanation:

a. The deposit

= 15% × $2975

= 15/100 × $2975

= 0.15 × $2975

= $446.25

b. The hire purchase price

Outstanding balance = $2975 - $446.25 = $2528.75

20% of outstanding balance

= 20% × $2528.75

= 0.2 × $2528.75

= $505.75

Hire purchase price

= $2975 + $505.75

= $3480.75

c. The difference the hire purchase price and cash price

= $3480.75 - $2975

= $505.75

d. The difference as a percentage of the cash price.

= ($505.75 / $2975) × 100

= 0.17 × 100

= 17%

5 0
3 years ago
Lines EC and HF are parallel CDG is congruent to dgh what is the measure of CDG
Verizon [17]
Angle ADC and EDG are congruent(vertical angles)
Same side interior angles are =180
2x+4x-30=180
6x-30=180
6x=210
x=35
CDG is congruent to DGH(alternate interior)
4x-30
4(35)-30
140-30
=110
5 0
2 years ago
In a competition, a school awarded medals in different categiories.40 medals in sport 25 medals in danceand 212 medals in music,
aleksley [76]

Answer:

210

Step-by-step explanation:

Given:

Medals in sports = 40

Medals in dance = 25

Medals in music = 212

Total students that received medals = 55

Total students that received medals in all three categories = 6

Required:

How many students get medals in exactly two of these categories?

Take the following:

A = set of persons who got medals in sports.

B = set of persons who got medals in dance

C = set of persons who got medals in music.

Therefore,

n(A) = 40

n(B) = 25

n(C) = 212

n(A∪B∪C)= 55

n(A∩B∩C)= 6

To find how many students get medals in exactly two of these categories, we have:

n(A∩B) + n(B∩C) + n(A∩C) −3*n(A∩B∩C)

=n(A∩B) + n(B∩C) + n(A∩C) −3*6 ……............... (1)

n(A∪B∪C)=n(A)+n(B)+n(C)−n(A∩B)−n(B∩C)−n(A∩C)+n(A∩B∩C)

Thus, n(A∩B)+n(B∩C)+n(A∩C)=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)

Using equation 1:

=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)−18

Substitute values in the equation:

= 40 + 25 + 212 + 6 − 55 − 18

= 283 - 73

= 210

Number of students that get medals in exactly two of these categories are 210

6 0
3 years ago
Approximate the square root to the nearest integer.<br> 37
REY [17]
6.083 would be the answer
8 0
3 years ago
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