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Readme [11.4K]
3 years ago
7

There are 80 sixth graders at Wilson Middle School. Only 70% of the sixth graders will attend the morning assembly. How many six

th graders will be at the morning assembly?
Mathematics
2 answers:
Nuetrik [128]3 years ago
6 0

The answer is 56 because

Recall that 70% is , and  is 0.70.


To find the number of sixth graders who will attend the morning assembly, multiply 80 by , or 0.70.




So, 56 sixth grade students will attend the morning assembly.[?][?][?][?][?][?][?][?]


zysi [14]3 years ago
4 0
1 student will attend the assembly in the morning
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The area of a square is 64n^36 units. What is the side length of one side of the square?
CaHeK987 [17]
√64= 8
√n³⁶= n¹⁸

Final answer: 8n¹⁸, or B
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3 years ago
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An object oscillates 4 feet from its minimum height to its maximum height. The object is back at the maximum height every 3 seco
bulgar [2K]

Answer:

y=2\text{cos}((\frac{2\pi}{3})t)

Step-by-step explanation:

We have been given that an object oscillates 4 feet from its minimum height to its maximum height. The object is back at the maximum height every 3 seconds. We are asked to find the cosine function that can be used to model the height of the object.

We know that standard form of cosine function is y = A\cdot \text{cos}(Bt-C)+D, where,

|A| = Amplitude,

Period = \frac{2\pi}{|B|},

C = Phase shift,

D = Vertical shift.

Since distance between maximum and minimum is 4, therefore, amplitude will be half of it, that is, A = 2.

Since objects gets back to its maximum value in every 3 seconds, therefore, period of the function is 3 seconds. We know that period is given by \frac{2\pi}{|B|}, therefore, we can write \frac{2\pi}{|B|}=3, therefore, B = \frac{2\pi}{3}.

We haven't been given any information about phase and mid-line, we can assume the values of C and D to be zero .

Therefore, our function required function would be y=2\text{cos}((\frac{2\pi}{3})t).

6 0
4 years ago
Reduce then multiply. <br><br> 7/9 x 3/4 = ?<br><br> Example :
ziro4ka [17]

First, we are going to want to see if there are any terms we can simplify. By examining the numerators and denominators of our functions, we can see that we can remove a 3 from the denominator of the second function and the numerator of the first function. This would be represented as:

\dfrac{7}{9} \cdot \dfrac{3}{4} = \dfrac{7}{3} \cdot \dfrac{1}{4}


Now, we can multiply the fractions. Remember that to multiply fractions, simply multiply both the numerators over both the denominators, as shown below:

\dfrac{a}{b} \cdot \dfrac{c}{d} = \dfrac{ac}{bd}


By applying this information, we can solve for the product of the fractions:

\dfrac{7}{3} \cdot \dfrac{1}{4} = \dfrac{7}{12}


Our answer is \boxed{\frac{7}{12}}.

8 0
3 years ago
PLS HELP! 20 points! U WILL BE BRAINMASTER
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