*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*
(21)
Area of a Regular Hexagon: 
square units
(22)
Similar to (21)
Area = 
square units
(23)
For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:
Hence, area of the hexagon will be: 
square units
(24)
Given is the inradius of an equilateral triangle.
Substituting the value of inradius and calculating the length of the side of the equilateral triangle:
Side = 16 units
Area of equilateral triangle = 
square units
11/12 + 1 3/4=
1 3/4 = 7/4 = 21/12
11/12 + 21/12 = 32/12 = 2 8/12 = 2 2/3 oz
Answer:
50
Step-by-step explanation:
For this question you would follow the BIDMAS rule - (Brackets, Indices, Division, Multiplication, Addition, Subtraction.)
The first thing in this question you need to solve it (9 + 8)
we do this because, when we follow BIDMAS, the first rule is brackets
so, 9 + 8 = 17
The second step is to multiply, as this rule is second,
so, 17 x 2 = 34
Our final step is to solve the last bit, which is 6 x 14
and we know that 6 x 14 = 84
So now that we have 84 and 34, we need to subtract the two numbers as shown,
84 - 34 = 50
And this is how you get the answer 50
i hope this has helped you, please comment if you did not understand it and i will explain it in another way : )
Answer:
1/2
Step-by-step explanation:
cot∅ = 1/tan∅
cot∅ = 1/2
