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3 years ago

If 2x +y=8, x+2y=4, find the value of x-y. Please, help me

Mathematics

1 answer:

kifflom [539]3 years ago

8 0

y = 8 -2x

x + 2 (8 - 2x) = 1

x + 16 - 4x = 1

x - 4x = -15

-3x = -15

x = 5

If x = 5, then we can substitute in...

5 + 2y = 1

2y = -4

y = -2

Now let us check that by substituting those values in to the equation

2x + y = 8

2 (5) + (-2) = 8

That is correct so we have the right values for x and y/

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Evaluate the indefinite integral. integar x4/1 + x^10 dx

ivann1987 [24]

Answer:

$\int\ {\frac{x^4}{1 + x^{10}}} \, dx = \frac{1}{5}( \arctan(x^5)) + c$

Step-by-step explanation:

Given

$\int\ {\frac{x^4}{1 + x^{10}}} \, dx$

Required

Integrate

We have:

$\int\ {\frac{x^4}{1 + x^{10}}} \, dx$

Let

$u = x^5$

Differentiate

$\frac{du}{dx} = 5x^4$

Make dx the subject

$dx = \frac{du}{5x^4}$

So, we have:

$\int\ {\frac{x^4}{1 + x^{10}}} \, dx$

$\int\ {\frac{x^4}{1 + x^{10}}} \, \frac{du}{5x^4}$

$\frac{1}{5} \int\ {\frac{1}{1 + x^{10}}} \, du$

Express x^(10) as x^(5*2)

$\frac{1}{5} \int\ {\frac{1}{1 + x^{5*2}}} \, du$

Rewrite as:

$\frac{1}{5} \int\ {\frac{1}{1 + x^{5)^2}}} \, du$

Recall that: $u = x^5$

$\frac{1}{5} \int\ {\frac{1}{1 + u^2}}} \, du$

Integrate

$\frac{1}{5} * \arctan(u) + c$

Substitute: $u = x^5$

$\frac{1}{5} * \arctan(x^5) + c$

Hence:

$\int\ {\frac{x^4}{1 + x^{10}}} \, dx = \frac{1}{5}( \arctan(x^5)) + c$

7 0

3 years ago

Solve using elimination y = 5x+4 y = 2x+7 Show work plz

Gre4nikov [31]

Answer and Step-by-step explanation:

5x + 4

2x + 7

Multiply 5x + 4 by 2, and 2x + 7 by 5.

10x + 8

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-27 is the answer

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3 0

3 years ago

help this is hard Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s

Nesterboy [21]

Answer:

x = $-\frac{3}{b}$

x = -1

Step-by-step explanation:

The given equation is,

-2(bx - 5) = 16

Dividing by (-2) on both sides of the equation,

$\frac{-2(bx-5)}{(-2)}=\frac{16}{(-2)}$

(bx - 5) = -8

By adding 5 on both the sides of the equation,

(bx - 5) + 5 = -8 + 5

bx = -3

Dividing by 'b' on both the sides of the equation,

$\frac{bx}{b}=\frac{-3}{b}$

x = $-\frac{3}{b}$

If b = 3,

x = $-\frac{3}{3}$

x = -1

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Anna [14]

Answer:

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Step-by-step explanation:

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Andrew [12]

Answer:

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Step-by-step explanation:

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