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tangare [24]
3 years ago
13

Write an equation in slope form for the line through the given point with the given slope?(8,3);m=5

Mathematics
1 answer:
Inessa05 [86]3 years ago
6 0
Ans:C.
Remember equation Y=MX, and M is Slope.
now we know the line through the given point <span>(8,3)
</span>so put (8,5) into the equation 
then equation Y=MX → (Y-3)=M(X-8)
and Slope M=5 
so (Y-3)=5(X-8)


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Metallic silver has a density of 10.50. what is the mass, in g, of a silver ingot that is 28.0 cm long, 4.90 cm wide, and 3.60 c
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Answer:

5190 g

Step-by-step explanation:

Calculate the volume:

28.0 cm × 4.90 cm × 3.60 cm = 493.92 cm³

Density is mass divided by volume:

D = M / V

Solving for mass:

M = D V

Substituting values:

M = (10.50 g/cm³) (493.92 cm³)

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3 years ago
Segment PH is graphed on the coordinate grid where P is (-31,8) and H is (29,-10). Point E is the midpoint of segment PH. If poi
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Answer:

The coordinates of point A are (-11 , 2)

Step-by-step explanation:

- The coordinates of point P are (-31 , 8)

- The coordinates of point H are (29 , -10)

- Point E is the mid-point of segment PH

- The coordinates of the the mid-point are:

→ x=\frac{x_{1}+x_{2}}{2} and y=\frac{y_{1}+y_{2}}{2}

∵ E is the mid-point of segment PH

∴ The x-coordinate of point E is x=\frac{-31+29}{2}=-1

∴ The x-coordinate of point E is -1

∴ The y-coordinate of point E is y=\frac{8+-10}{2}=-1

∴ The y-coordinate of point E is -1

∴ The coordinates of point E are (-1 , -1)

- Point A is graphed \frac{2}{3} of the way along the segment from P to E

- That mean the distances from points P to A is 2 parts and from P to E

  is 3 parts, then the distance from A to E is "3 - 2" = 1 part

- So point A divides the line segment PE at ratio 2 : 1 from P

- The coordinates of the division point are:

→ x=\frac{x_{1}m_{2}+x_{2}m_{1}}{m_{1}+m_{2}} and y=\frac{y_{1}m_{2}+y_{2}m_{1}}{m_{1}+m_{2}}

∵ Point A divides PE at ratio 2 : 1

∵ The coordinates of point P are (-31 , 8)

∵ The coordinates of point E are (-1 , -1)

∴ The x-coordinate of point A is x=\frac{(-31)(1)+(-1)(2)}{2+1}= -11

∴ The x-coordinate of point A is -11

∴ The y-coordinate of point A is x=\frac{(8)(1)+(-1)(2)}{2+1}=2

∴ The y-coordinate of point A is 2

∴ The coordinates of point A are (-11 , 2)

* The coordinates of point A are (-11 , 2)

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