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ddd [48]
3 years ago
14

Find 2 numbers which multiply to give 45 and add up to 44

Mathematics
2 answers:
zysi [14]3 years ago
8 0
I think the number should be (-45), not 45. IF this is the case:
(45) + -1 = 44
(45) x -1 = -45
Having the two numbers 45 and 44 makes this equation impossible
Your two numbers are: 45, and -1
DaniilM [7]3 years ago
5 0
Lets first make the factors
<span>1* 45 = 45
3 * 15 = 45
5 * 9 = 45
</span>So, we can pick up our number from here..

45 * 1 = 45
45 - 1 = 44

So your 2 numbers are 1 and 45..

Hope this helps..  :) 
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Answer: The correct options are  (1) (5,10), (2) (3,-3), (3) x = -1, (4) y=(x+2)^2+3, (5) 21s and (6) 0, -1, and 5.

Explanation:

Te standard form of the parabola is,

f(x)=a(x-h)^2+k        .....(1)

Where,  (h,k) is the vertex of the parabola.

(1)

The given equation is,

f(x)=(x-5)^2+10

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The given equation is,

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f(x)=3(x^2-6x)+24

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f(x)=3(x^2-6x+9)+24-3\times 9

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h=3 and k=-3

Therefore, the vertex of the graph is (3,-3) and the fourth option is correct.

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The given equation is

f(x)=4x^2+8x+7

f(x)=4(x^2+2x)+7

To make perfect square add (\frac{b}{2a})^2, i.e., 1. Since there is factor 4 outside the parentheses, so subtract three times of 1.

f(x)=4(x^2+2x+1)+7-4

f(x)=4(x+1)^2+3

Comparing this equation with equation (1),we get,

h=-1 and k=3

The vertex of the equation is (-1,3) so the axis is x=-1 and the correct option is 2.

(4)

The given equation is,

y=x^2+4x+7

To make perfect square add (\frac{b}{2a})^2, i.e., 2^2.

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The given equation is,

h=-16t^2+672t

It can be written as,

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x=0,-1,5

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