Question

An empty 5 gallon water jug weighs 0.75 lbs. With 3 cups of water inside, the jug weighs 2.25 lbs. What equation models the jug's weight y when it contains x cups of water?

Answer 1

Answer:

Step-by-step explanation:

3 cups of water + jug = 2.25 lbs

jug = .75 lbs

3 cups of water = 1.5 lbs

1 cup of water = .5 lbs

Therefore,

y = .75 + .5x

Answer 2

Answer: jugs weight ⇒ y = 0.75 + 0.5 x

Step-by-step explanation:

Hi, to solve this problem we have to analize the information given.

So:

Empty jug weight = 0.75 lbs

jug with 3 cups of water weight =2.25

The next step is to subtract the weight of the empty jug to the weight of the jug with 3 cups.

2.25 -0.75= 1.5 lbs

We have calculated the weight of 3 cups of water. To calculate the weight of one cup we simply divide the result by 3.

1.5 /3 = 0.5 lbs ( 1 cup)

Finally, we have the information needed for the equation. It wiil be the weight of the empty jug plus the weight of one cup of water multiplied by x.

jugs weight (y) = 0.75 + 0.5 x

Feel free to ask for more if it´s necessary or if you did not understand something