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kobusy [5.1K]
3 years ago
14

12h = 132 h= i need to know how to do that ^

Mathematics
2 answers:
Wittaler [7]3 years ago
8 0

Answer:

h=11

Step-by-step explanation:

divide:

132/12h

11h

Len [333]3 years ago
6 0

Answer:

11

Step-by-step explanation:

You divide each side by 12 in order to isolate the h

So: 12h = 132

     ____  _____

      12        12

       h   =     11

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kolezko [41]

Answer:

256inches

Step-by-step explanation:

8×16 + 8×16

128+128=256

3 0
3 years ago
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Find the distance between points (-3,-4) and (1,-2)
Ludmilka [50]

Answer:

√20 or 4.47 ish

Step-by-step explanation:

√(1--3)²+(-2--4)²

√(1+3)²+(-2+4)²

√(4)²+(2)²

√16+4

√20

4.47 ish

(Hopefully this is correct, have a nice day!)

6 0
3 years ago
What were the factor(s), levels, and treatments for this experiment?
wolverine [178]

Step-by-step explanation:

A factor is an independent variable that is manipulated in an experiment.

Every factor has two or more levels, which are different values of the factor.

A combination of factor levels is called a treatment.

There is one factor: number of jumps.

This factor has two levels: sets of 10 and sets of 20.

For a single factor experiment, the levels are also the treatments: Jump 10 program and Jump 20 program.

8 0
3 years ago
Three DVDs and four CDs cost $92. Two DVDs and three CDs cost
Vedmedyk [2.9K]

Answer:

DVD: $16

CD: $11

Step-by-step explanation:

These two linear equations can represent the system of equations where x equals the cost of a DVD and y equals the cost of a CD:

3x+4y=92

2x+3y=65

When graphed, the solution is at (16,11).

Therefore, one DVD costs $16 and one CD costs $11.

8 0
2 years ago
The radius of a spherical balloon is measured as 20 inches, with a possible error of 0.03 inch. Use differentials to approximate
soldi70 [24.7K]

Answer:

a) V = 33510.322\,in^{3}, b) A_{s} = 5026.548\,in^{2}, c) \% V = 0.450\,\%, \%A_{s} = 0.300\,\%.

Step-by-step explanation:

The volume and the surface area of the sphere are, respectively:

V = \frac{4}{3}\pi \cdot r^{3}

A_{s} = 4\pi \cdot r^{2}

a) The volume of the sphere is:

V = \frac{4}{3}\pi \cdot (20\,in)^{3}

V = 33510.322\,in^{3}

b) The surface area of the sphere is:

A_{s} = 4\pi \cdot (20\,in)^{2}

A_{s} = 5026.548\,in^{2}

c) The total differentials for volume and surface area of the sphere are, respectively:

\Delta V = 4\pi\cdot r^{2}\,\Delta r

\Delta V = 4\pi \cdot (20\,in)^{2}\cdot (0.03\,in)

\Delta V = 150.796\,in^{3}

\Delta A_{s} = 8\pi\cdot r \,\Delta r

\Delta A_{s} = 8\pi \cdot (20\,in)\cdot (0.03\,in)

\Delta A_{s} = 15.080\,in^{2}

Relative errors are presented hereafter:

\%V = \frac{\Delta V}{V}\times 100\%

\%V = \frac{150.796 \,in^{3}}{33510.322\,in^{3}}\times 100\,\%

\% V = 0.450\,\%

\% A_{s} = \frac{\Delta A_{s}}{A_{s}}\times 100\,\%

\% A_{s} = \frac{15.080\,in^{2}}{5026.548\,in^{2}}\times 100\,\%

\%A_{s} = 0.300\,\%

4 0
3 years ago
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