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Ganezh [65]
3 years ago
12

A science teacher wrote the table of values below.

Mathematics
2 answers:
Umnica [9.8K]3 years ago
5 0
C. f(x)= log 1/x^2 , c=/ 0

ololo11 [35]3 years ago
5 0

Answer:

C. f(x)= log 1/x , x =/ 0.

Step-by-step explanation:

Given : A science teacher wrote the table of values below.

To find : Which function models the data in the table.

Solution : We have given table with x and f(x ).

We can see from table  if x = \frac{1}{10} then f(x) =1

By logarithm rule : log (10) = 1 , log (100) = 2.

Substitute the values of x in f(x)= log\frac{1}{x}.

If  x =  \frac{1}{10} .

f(x)= log\frac{1}{(\frac{1}{10})}.

We can write it f(x) = log(10) = 1

If  x =  \frac{1}{100} .

f(x)= log\frac{1}{(\frac{1}{100})}.

We can write it f(x) = log(100) = 2

Therefore, C. f(x)= log 1/x , x =/ 0.

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A politician estimates that 61% of his constituents will vote for him in the coming election. How many constituents are required
Katyanochek1 [597]

Using the z-distribution, as we are working with a proportion, it is found that 1016 constituents are required.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
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The margin of error is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

The estimate is of \pi = 0.61, while the margin of error is of M = 0.03, hence solving for n we find the minimum sample size.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.61(0.39)}{n}}

0.03\sqrt{n} = 1.96\sqrt{0.61(0.39)}

\sqrt{n} = \frac{1.96\sqrt{0.61(0.39)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.61(0.39)}}{0.03}\right)^2

n = 1015.5

Rounding up, 1016 constituents are required.

More can be learned about the z-distribution at brainly.com/question/25890103

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Step-by-step explanation:

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