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RideAnS [48]
3 years ago
7

multiply or divide SHOW YOUR WORK!!!! 3n^2-3 over n^2-1 divided by n^2 over n+1 SHOW YOUR WORK!!!!!

Mathematics
1 answer:
Bogdan [553]3 years ago
4 0
Here, 3n² - 3 / n² - 1  * (n + 1) / n²
= 3(n² - 1) / (n² - 1) * (n + 1) / n²
= 3(n + 1) / n²
= 3n + 3 / n²

In short, Your Answer would be: (3n + 3) / n²

Hope this helps!
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30 ptss!! Simplify the following expression.<br> 3^0
ivolga24 [154]

Answer:

1

Step-by-step explanation:

anything with an exponent of 0 is equal to one. ex. 4^0=1, 20^0=1.

7 0
4 years ago
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The functions graphed show the snowfall, in inches, in two cities after x hours.
xenn [34]
The answer Fam is............. <span>Smithville had a faster rate of snowfall., And..</span><span>Snow fell in Smithville at a rate of 4 inches per hour.</span>
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4 years ago
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The first one TO GET IT CORRECT will get brainliest plus 11 points :)
olya-2409 [2.1K]

Answer:

6 x 2.5 = 15

8 x 2.5 = 20

L x W = 300 square units

Step-by-step explanation:

Brainliest?

4 0
3 years ago
SOMEONE ANSWER PLEASE PLEASE
Gnom [1K]

Answer:

See explanation below.

Step-by-step explanation:

Let's say,

x = number of tokens required to play one game of ping pong

y = number of token required play one game of pinball

Using the data given, the system of equations are:

\begin{bmatrix}9x+5y=29\\ 3x+y=7\end{bmatrix}

Solving the system of equations using substitution method will give us:

y=4\:\:\:,\:\:\:x=1

So, one game of ping pong required 1 token, whereas one game of pinball required 4 tokens.

3 0
4 years ago
Can y’all help me answer these questions
cupoosta [38]

2. f(x)=\dfrac18\left(\dfrac14\right)^{x-2}

Domain: (-\infty,\infty), because any value of x is allowed and gives a number f(x).

Range: (0,\infty), because a^x>0 for any positive real a\neq0.

y-intercept: This is a point of the form (0, f(0)). So plug in x=0; we get f(0)=\frac18\left(\frac14\right)^{-2}=\frac{4^2}8=2. So the intercept is (0, 2), or just 2. (Interestingly, you didn't get marked wrong for that...)

Asymptote: This can be deduced from the range; the asymptote is the line y=0.

Increasing interval: Going from left to right, there is no interval on which f(x) is increasing, since 1/4 is between 0 and 1.

Decreasing interval: Same as the domain; f(x) is decreasing over the entire real line.

End behavior: The range tells you f(x)>0, and you know f(x) is decreasing over its entire domain. This means that f(x)\to+\infty as x\to-\infty, and f(x)\to0 and x\to+\infty.

3. f(x)=\left(\dfrac32\right)^{-x}-7

Domain: Same as (2), (-\infty, \infty).

Range: We can rewrite f(x)=\left(\frac23\right)^x-7. \left(\frac23\right)^x>0 for all x, so \left(\frac23\right)^x-7>-7 for all x. Then the range is (-7,\infty).

y-intercept: We have f(0)=\left(\frac32\right)^0-7=1-7=-6, so the intercept is (0, -6) (or just -6).

Asymptote: y=-7

Increasing interval: Not increasing anywhere

Decreasing interval: (-\infty,\infty)

End behavior: Similar to (2), but this time f(x)\to+\infty as x\to-\infty and f(x)\to-7 as x\to+\infty.

5 0
4 years ago
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