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3 years ago

An element with a mass of 600 grams decays by 27.8% per minute. To the nearest

Mathematics

1 answer:

UNO [17]3 years ago

4 0

Answer:

17.5 minutes

Step-by-step explanation:

i just put 600 times 0.722^x=2 in desmos graph and got that

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If the volume of a cube is increased by a factor of 10 (so that the new volume is 10 times the size of the original volume), by

Alexeev081 [22]

Answer:

surface area of cube $10^{\frac{2}{3} }$ time

Step-by-step explanation:

given data

new volume = 10 time original volume

to find out

what factor surface area change

solution

we consider here side of cube is a

and volume is V

we consider here a is 2

then volume will be v1 = a³ = 2³ = 8

and surface area = 6a² = 6(2)² = 24 ..........1

so if volume increase 10 time

than

V = 10 × v1

a³ = 10 × 8

a³= 80

a = 2 × ∛10

and

surface area increase here

surface area = 6a²

surface area = 6( 2 × ∛10 )²

surface area = 24 × $10^{\frac{2}{3} }$ ............2

so from equation 1 and 2

surface area / surface area = 24 × $10^{\frac{2}{3} }$ / 24

surface area = $10^{\frac{2}{3} }$

so here surface area of cube will be $10^{\frac{2}{3} }$ time

5 0

4 years ago

The vertices of rectangle WXYZ are W(-4, -3), X(-4,1), and Y(2, 1). a. What are the coordinates of the fourth vertex? b. Find th

vekshin1

Answer:

a: (2, -3)

b: 20

c: 24

4 0

2 years ago

Is this a function? yes or no picture included ^^^^

aliya0001 [1]

Answer:

Yes this is a function because when doing the straight line test it doesn't touch it two or more times.

8 0

2 years ago

Consider the equation q= 4 +0.8p. What value of q would make the equation true when p is 7?

NARA [144]

Answer:

9.6

Step-by-step explanation:

q=4+0.8(7)

6 0

3 years ago

What is the interquartile range of the data set

Verizon [17]

There are many methods of doing this. This one finds the median; however, instead of halving, you can use quarters instead.

First order the data, ascendingly:

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

Find the median:

For an even number of values: The number of values / 2

For an odd number of values: The number of values + 1 / 2

11 is odd.

11 + 1 / 2

12 / 2 = 6

The median is at the 6th position.

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

The median is 20.

Other method:

You don't need this step.

Using the values lower than the median, exclusive, find the median of the lower values;

For an odd number of values: The number of values + 1 / 2

10, 17, 18, 18, 18

5 + 1 / 2 = 6 / 2 = 3

The median of the lower values is at position 3.

This is the lower quartile.

10, 17, 18, 18, 18

Other method:

For an odd number of values: The number of values + 1 / 4

11 + 1 / 4 = 12 / 4 = 3

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

Using the values greater than the median, exclusive, find the median:

For an odd number of values: The number of values + 1 / 2

20, 25, 25, 30, 30

5 + 1 / 2 = 6 / 2 = 3

The median of the upper values is at position 3.

20, 25, 25, 30, 30

This is 25.

This is the upper quartile.

Other method:

For an odd number of values: (The number of values + 1 / 4) * 3

(11 + 1 / 4) * 3 = (12 / 4) * 3 = 3 * 3 = 9

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

Your interquartile range is 3 - 25

25 - 3 = 21

8 0

3 years ago