Since they are similar, the dimensions are in the same ratio. L1 = 5, L2 = 15, so they are in a 3:1 ratio. So if V1 = 60, then W1×H1 = 60/5 = 12
W2 must also be 3×W1 and H2 3×H1, and
3×3 = 9. So take 12×9 (W×H1×9) ×15 (L2) = V2
V2 = 12×9×15 = 1620 cm^3
Let me know the right answer when you find out!
Answer:
24
Step-by-step explanation
-|-|-|-|-|-|-|-|-|-|-|-|-|-|-|-|-|-|-|-|--|-|-|-|
Simplified. Employ photomath for more detailed explanation.
The appropriate response is a weighted average. It is a mean ascertained by giving qualities in an informational index more impact as indicated by some characteristic of the information. It is normal in which every amount to have arrived at the midpoint of is allocated a weight, and these weightings decide the relative significance of every amount on the normal.
Given:
The two functions are:
To find:
The value of 
.
Solution:
We have,
We know that,
![(h\circ g)(b)=[(5b-9)-1]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28b%29%3D%5B%285b-9%29-1%5D%5E2)
![(h\circ g)(b)=[5b-10]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28b%29%3D%5B5b-10%5D%5E2)
Putting 
, we get
![(h\circ g)(-6)=[5(-6)-10]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28-6%29%3D%5B5%28-6%29-10%5D%5E2)
![(h\circ g)(-6)=[-39-10]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28-6%29%3D%5B-39-10%5D%5E2)
![(h\circ g)(-6)=[-49]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28-6%29%3D%5B-49%5D%5E2)
Therefore, the value of is 2401.
