Hi there!
![\large\boxed{\text{Gradient = -1}}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%5Ctext%7BGradient%20%3D%20-1%7D%7D)
We can find the slope using the slope formula:
Slope = (y2-y1)/(x2-x1)
Plug in the given coordinates:
Slope = (1 - 5)/(7 - 3)
Simplify:
Slope = -4/4
Slope = -1
Answer:
why
Step-by-step explanation:
a. To solve this, we should make a combination
![\begin{gathered} nCr=\frac{n!}{r!(n-r)!} \\ 24P5=\frac{24!}{5!(24-5)!}=42504 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20nCr%3D%5Cfrac%7Bn%21%7D%7Br%21%28n-r%29%21%7D%20%5C%5C%2024P5%3D%5Cfrac%7B24%21%7D%7B5%21%2824-5%29%21%7D%3D42504%20%5Cend%7Bgathered%7D)
5 person committee can be chosen in 5100480 different ways
b. To find this probability (A), we should use the answer of the last question as the total cases, and the favourable cases will be the shown combinations
![P(A)=\frac{7C3\cdot17C2}{42504}](https://tex.z-dn.net/?f=P%28A%29%3D%5Cfrac%7B7C3%5Ccdot17C2%7D%7B42504%7D)
Calculate the combinations
Answer:
An interval that will likely include the proportion of students in the population of twelfth-graders who carry more than $15 is 960
Step-by-step explanation:
For example, Condition 1: n(.05)≤N
• The sample size (10) is less than 5% of the population (millions of musicians), so
the condition is met.
• Condition 2: np(1-p)≥10
• =
2
10
= .2
• 1 − = 10 .2 1 − .2 = 1.6 . This is less than 10 so this condition is not
met.
It would not be practical to construct the confidence interval.
We are given the function: <span> 1 divided by the quantity x minus 2 squared and is asked in the problem to determine the limit of x as x approaches 2 as well as vertical asymptotes if there are any. To find the limit, we just have to substitute the equation with the value of the numerical limit. The equation then becomes, 1/ (x-2)^2 = 1/(2-2)^2 = 1/0 . Any number divided by zero is equal to infinity so the limit is infinity. A vertical asymptote is the value of x in which the denominator becomes zero, that is (x-2)^2 = 0; x = 2. The vertical asymptote is equal to 2.</span>